in verification of ohms law the mass is 100g, initial length is 31, final length is 31.3 what is the extension?
1 answer:
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Answer:
<em>866.1 N</em>
Explanation:
The torque on the flywheel = 300 N-m
The force from the hydraulic cylinder will generate a moment on CA about point A.
The part of this moment that will be at point B about A must be proportional to the torque on the cylinder which is 300 N-m
we know that moment = F x d
where F is the force, and
d is the perpendicular distance from the turning point = 1 m
Equating, we have
300 = F x 1
F = 300 N this is the frictional force that stops the flywheel
From F = μN
where F is the frictional force
μ is the coefficient of static friction = 0.4
N is the normal force from the hydraulic cylinder
substituting, we have
300 = 0.4 x N
N = 300/0.4 = 750 N
This normal force calculated is perpendicular to CA. This actual force, is at 30° from the horizontal. To get the force from the hydraulic cylinder R, we use the relationship
N = R sin (90 - 30)
750 = R sin 60°
750 = 0.866R
R = 750/0.866 = <em>866.1 N</em>
Answer:
Speed=1.633 m/s
Force= 20 N
Explanation:
Ideally, hence
where v is the speed of collar, m is the mass of collar, k is spring constant and s is the displacement.
In this case, s=100-0=100mm=0.1m since 1 m is equivalent to 1000mm
k is given as 200 N/m and mass is 0.75 Kg
Substituting the given values
Therefore, <u>the speed is 1.633 m/s</u>
The sum of vertical forces is given by mg where g is acceleration due to gravity and it's value taken as
Therefore,
The sum of forces in normal direction is given by therefore
Therefore, <u>normal force on the rod is 20 N</u>
Answer:
Condition A
Heat flux is 1400 W/M^2
Condition B
Heat flux is 12800 w/m^2
Explanation:
Given that:
is given as 30 degree celcius
condition A
Air temperature = - 5 degree c
convection coefficient h = 40 w/m^2. k
condition A
water temperature = 10 degree c
convection coefficient = 800 w/m^2.k
Answer:
- <u>0.59</u>
Explanation:
The <em>batch</em> is <em>rejected</em> if any of the <em>random samples are found defective</em>, or, what is the same, it will be accepted only if all 15 samples are good.
The probability that none be defective is the same probability that all the samples are good. Thus, start to calculate the probability that the batch is accepted.
The probability that the first sample is good is 214 /225, because there are 225 - 11 = 214 good samples in 225 doses.
The probability that the second samples is good too is 213/224, because there is 1 less good sample, in the 224 remaining samples.
By the same process, you conclude that the consecutive probabilities of selecting a good sample are: 212/223, 211/222, 210/221, . . . up to 199/211.
The joint probability of all the samples are good is the product of each probability:
The result is: 0.41278 ≈ 0.41
The conclusion is that the probability that all the samples are good and the batch is accepted is 0.41.
Therefore, <em>the probability that the batch is rejected</em> is 1 - 0.41 = 0.59.