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navik [9.2K]
4 years ago
6

Nicholas wants to verify whether a file is a hard link to a file within the same directory. Which of the following commands coul

d he use to see information that would be helpful to make this determination?
a.
ls -al

b.
ls -i

c.
ls -s

d.
ls -l
Engineering
1 answer:
garri49 [273]4 years ago
5 0

Answer:

d

Explanation:

Is is used to display files in a directory.  Is-l is used to see total information about a file including how many hardlink files are there in the directory.

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For the following production environments, indicate whether the preferred production system is more likely to be a job shop (pro
Nina [5.8K]

Answer:

A) Batch shop production

B) Batch shop production

C) Job shop production

D) production line

Explanation:

A)The preferred production system here will be  Batch shop production because the manufacturer produces different styles of clothing and sells to small specialty stores hence producing in Batches can help meet up the needs

B) The preferred production system here will be Batch shop production because the manufacturer produces Gaskets and they are of different styles hence he needs to produce them in batches

C) Job shop production

D) production here is streamlined to a particular ( tablet form ) hence the production system here would be a Production line system of production

3 0
3 years ago
Question 11 (1 point)
kirill115 [55]

Answer:

  False

Explanation:

Bella counts products in finished goods inventory and she counts kits in various stages of manufacturing.

4 0
3 years ago
Velocity boundary layer thickness over a intermal fixed horizontal flat plate is the________ distance required for the fluid vel
antoniya [11.8K]

Answer:

Velocity boundary layer thickness over an internal or internal fixed flat plate is  normal to surface distance  required for the fluid velocity to attain the 99% of the free stream velocity value.

Explanation:

The affirmation is the current definition of velocity boundary layer thickness.

4 0
3 years ago
Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these d
Tems11 [23]

Complete Question

Lumber jacks use cranes and giant tongs to hoist their goods into trucks for transport. Fortunately, smaller versions of these devises are available for weekend warriors who want to play with their chain saws. Let us model the illustrated tongs as a planar mechanism that carries a log of weight 210 N. Given the following dimensions: 35 mm 10 mm 40 mm 230 mm 85 mm 45 mm 10 mm 35 mm 345 mm determine the force in N and moment in Nm that our worker exerts on the tongs. Also determine the pinching force magnitude in N that the tongs exert on the log; i.e. determine the horizontal force that the tong's teeth exert on the log. Assume the  point E is centered between the tong's teeth.

The diagram for this question is shown on the first uploaded image

Answer:

The force P is P= 210 N

and the moment M is M = -48.3N \cdot m

The horizontal force that the tong teeth exerts is F_T =89.67N

Explanation:

First let denote the dimension to corresponding to the diagram

      a=35mm , b= 10mm, c= 40mm, d= 230mm, e= 85mm,f= 45mm,\\g= 10mm,h=35mm,i=345mm.

Next looking at the diagram let us consider the vertical direction

At equilibrium

               \sum F_{vertical} =0

This mean that

               P+ W = 0

Since they are acting in opposite direction the equation becomes

               P - W = 0

=>           P= W

=>            P= 210 N

At Equilibrium  Moment about F gives

               \sum M_f  = 0

=> F_T * (e +f + g+ h+ i) - F_T * (e+ f+g+ h+i) - W *d -M =0

=> M = -W *d

=> M = -210 * 0.230

=> M = -48.3N \cdot m

Here F_T is the horizontal force that the tong teeth exerts

Now let consider the part BAF of the system as shown on the second uploaded image

  Now the angle \theta is mathematically given as

             tan \theta = \frac{g+h}{a}

=>        \theta = arctan \frac{g+h}{a}

                = arctan (\frac{10+35}{35} )

               =52.125^o

Now at equilibrium the moment about A is

                \sum M_A = 0

          =>  P * (c+d) +M + F_{BC} cos \theta *f+F_{BC}sin\theta *(a+b) =0

                210 * (0.040 + 0.230)-48.3+F_{BC} cos (52.125^o)*0.045+ F_{BC}sin(52.125^o)* (0.035 +0.010) =0

    =>   10.29 +F_{BC} (0.02763+0.03552) =0

    =>     F_{BC} =\frac{10.29}{0.06315}

    =>      F_{BC} = - 162.925 N

Looking at the forces acting on the teeth as shown on the third uploaded image

 At Equilibrium the moment about D is

      \sum M_D = 0

=>  \frac{W}{2} *d - F_T *(i+h) -F_{BC} cos \theta *h -F_{BC} sin \theta * (b+c) =0

=>   \frac{210}{2} * 0.230 -F_T (0.345 +0.035) - (-162.925)cos(52.125^o) *0.035\\-(-162.925)sin(52.125^o)(0.010 +0.040) =0

=>    34.081  = F_T(0.345 +0.035)

=>   F_T =89.67N

         

   

         

7 0
4 years ago
Instrument panel help please
nirvana33 [79]

Answer:

A. 4WD Low

B. 4WD High

C. Safety belt

D. Check gauge

E. Oil temperature gauge

F. Left turn indicator

G. Tachometer

H. High beams

I. Speedometer

J. Right turn indicator

K. Battery voltage gauge

L. Cruise control light

M. (can't see sorry)

N. Service engine soon

O. Battery warning light

P. Airbag indicator

Q. Anti-lock brake system

R. Fuel gauge

S. Parking brake (AKA emergency brake) on

T. Low windshield washer fluid

U. Check fuel cap

V. Door ajar/open

W. Shift indicator

X. Trip odometer reset

Y. Oil pressure gauge

Z. compass/cardinal direction indicator

AA. Odometer?

4 0
3 years ago
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