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svp [43]
3 years ago
9

A toy factory sold 120,587 toys in 25 days. If each toy was sold for $58, about how much money did the factory earn in 25 days?

Estimate the answer by rounding off the number of toys to the nearest thousand.
Mathematics
1 answer:
Rina8888 [55]3 years ago
6 0
<h3>Answer: $7,018,000</h3>

This value is a little over 7 million dollars

======================================================

Explanation:

120,587 rounds to 121,000 when rounding to the nearest thousand.

The instructions don't mention rounding 58, so we'll leave it as that

Multiply the values to get

58*121,000 = 7,018,000

which is the estimate of how much money was earned.

-----------

The actual amount of money earned is

58*120,587 = 6,994,046

which isn't too far off of our estimate.

-----------

Note: the value of 25 days is never used. You could have any other number of days you want, and the answer is still the same. This value is probably either filler or some kind of distraction.

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There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

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Let's put more details in the figure to better understand the problem:

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For x, we will be using the Cosine Function:

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For y, we will be using the Sine Function.

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