Carl’s monthly income is $4,000. The circle graph below shows Carl’s monthly budget.

Identify the minimum or maximum value and the domain and range of the function

sdas [7]

Y = 2 ( X - 3 ) ^ 2 - 4 =-4

6 0

2 years ago

OH NO!!! Madeleine’s data has been corrupted, again! Using the incomplete data file below, which she was able to recover from he

-Dominant- [34]

Answer:

a. N=25

b. X[bar]= 60.52

c. Y[bar]= 106.72

d. SSx= 115.24

e. ∑X*∑Y = 4036684

f. SSxy= 202020.3296

g. √(SSx*SSy)= 449.46

Step-by-step explanation:

Hello!

Using the attached data you need to calculate some statistics.

a) N

The sample size is listed under the first column "subject" You can see that 25 subjects qhere studied so N=25.

b.

The mean of set X is equal to X[bar]= ∑X/n= 1513/25= 60.52

∑X is listed in the second table.

c.

The mean of ser Y is Y[bar]= ∑Y/n= 2668/25= 106.72

∑Y is listed in the second table.

d.

Sum of Squares of set X SSx= ∑X²-[(∑X)²/n]= 91682-[(1513)²/25]= 115.24

e.

∑X*∑Y =1513*2668= 4036684

f.

SSxy= (∑X²-[(∑X)²/n]) * (∑Y²-[(∑Y)²/n])= (91682-[(1513)²/25]) * (286482*[(2668)²/25])= 202020.3296

g.

√(SSx*SSy)= √(115.24*1753)= 449.46

I hope you have a SUPER day!

3 0

2 years ago

What is the solution of the equation when solved using the quadratic formula?<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B

Artemon [7]

Answer:

$x=\pm2i\sqrt{5}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Standard Form: ax² + bx + c = 0
Quadratic Formula: $x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

Algebra II

Imaginary Numbers: √-1 = i

Step-by-step explanation:

Step 1: Define Equation

x² + 20 = 0

Step 2: Identify Variables

a = 1

b = 0

c = 20

Step 3: Find roots x

Substitute: $x=\frac{-0\pm\sqrt{0^2-4(1)(20)} }{2(1)}$
Exponents: $x=\frac{-0\pm\sqrt{0-4(1)(20)} }{2(1)}$
Multiply: $x=\frac{-0\pm\sqrt{0-80} }{2}$
Subtract: $x=\frac{\pm\sqrt{-80} }{2}$
Factor: $x=\frac{\pm\sqrt{-1} \sqrt{80} }{2}$
Simplify: $x=\frac{\pm4i\sqrt{5} }{2}$
Divide: $x=\pm2i\sqrt{5}$

6 0

2 years ago

In a particular month, Ezhil spent one-fifth of her salary on shopping. Two-fifth of the remaining she gave to her sister. If sh

Oxana [17]

Answer:

$Salary = Rs23000$

Step-by-step explanation:

Given

$Shopping = \frac{1}{5}$

$Sister = \frac{2}{5}R$

$Left over = Rs11,040$

Required

Her salary in that month

Given that she spent $\frac{1}{5}$ of her salary on shopping, this implies that she has $\frac{4}{5}$ of her salary left

From what's left, she gave her sister $\frac{2}{5}$

This means she gave her sister $\frac{2}{5} * \frac{4}{5}$

Sister = $\frac{8}{25}$

Calculating a fraction of what's left

$Left over = 1 -Shopping - Sister$

$Left over = 1 - \frac{1}{5}- \frac{8}{25}$

$Left over = \frac{25 - 5 - 8}{25}$

$Left over = \frac{12}{25}$

Recall that she has Rs11,040

This means that

$\frac{12}{25} of Salary = Rs11,040$

Multiply both sides by $\frac{25}{12}$

$\frac{12}{25} * \frac{25}{12} * Salary = Rs11,040 * \frac{25}{12}$

$Salary = Rs11,040 * \frac{25}{12}$

$Salary = \frac{Rs276000}{12}$

$Salary = Rs23000$

Hence, her salary for that month was Rs23000

5 0

2 years ago

Read 2 more answers

Explain why angle is considered a defined term in geometry.

77julia77 [94]

Answer:

An angle is considered a defined term in geometry because defined terms are terms that have a formal definition and can be defined using other geometrical terms.

Angle: Two rays that share the same endpoint, however, the rays take off in different directions. The area in the middle of the two rays is the angle measure.

5 0

2 years ago