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kkurt [141]
3 years ago
13

What is an ordered pair (x,y) that is a solution to x-3y=3

Mathematics
1 answer:
Alina [70]3 years ago
6 0

Answer:

an ordered pair could be (9,2)

You might be interested in
How do i factor s^2+9s=-20
Talja [164]
To factor you have to do this: 

s^2 + 9s = -20
      + 20    +20

s^2 + 9s + 20 = 0

now you need to numbers that multiplied give you 20 
and then those same 2 numbers have to add to 9

5 x 4 = 20
5+ 4 = 9

(x + 4) (x+ 5)

that means that x= -4, and -5
8 0
4 years ago
Show work please i will give brailiest show work pls
Crank
1. 2-1+5x4x11
5x4=20
2-1+20x11
20x11=220
2-1+220
2-1=1
1+220=221

2. 14/2-1+3
14/2=7
7-1+3
7-1=6
6+3=9

3. 3x8x2-42+5
3x8=24
24x2-42+5
24x2=48
48-42+5
48-42=6
6+5=11
5 0
3 years ago
Solve: (6x2 + 5x + 1) + (x + 2).
Mademuasel [1]

Answer:

6x+6x2+3

Step-by-step explanation:

6x2+5x+1+x+2

Combine 5x and x to get 6x.

6x2+6x+1+2

Add 1 and 2 to get 3.

6x2+6x+3

7 0
2 years ago
Determine the Cartesian coordinates of the points with polar coordinates (\sqrt{2}, \pi/4 ), (0, \pi), (-1,400\pi), and ( 2\sqrt
yarga [219]

Answer:

Step-by-step explanation:

We have the conversion from polar coordinates to cartesian as

x =rcost and y = rsint where (r,t) are the polar coordinates

Also all trignometric functions are periodic with period = 2pi

Using this we find out

(\sqrt{2}, \pi/4 ) = (\sqrt{2}cos \pi/4, \sqrt{2}cos \pi/4,)=(1,1)\\ (0, \pi), (-1,400\pi),=(0 cos 1400 \pi, 0 sin 1400\pi)\\= (0, 0)\\\\ ( 2\sqrt{3},- 2\pi / 3) = (2\sqrt{3}, cos2\pi / 3, 2\sqrt{3},sin2\pi / 3))\\=(-\sqrt{3}, 3)

Thus we converted polar to rectangular coordinates.

Reverse would be

from (x,y) to (r,t) as

r=\sqrt{x^2+y^2} \\tant = y/x

8 0
3 years ago
I have 3 hundreds 17 tens 13 ones 1 tenths and 2 hundredths
Rashid [163]
If you're asking for the number, then it's 483.12
5 0
3 years ago
Read 2 more answers
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