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nexus9112 [7]
3 years ago
13

What is the number for thirty-nine million five thousand in standard form

Mathematics
1 answer:
hammer [34]3 years ago
5 0
395,000,000 i think not sure
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PLEASE HURRY IT'S URGENT!!!!!
kramer

Answer:

none of those answers are right, because the base of the triangle at 7/24 ft (or 0.29 ft) is smaller than the height 1/3 ft (or 0.33 ft)

Step-by-step explanation:

7/24 - 1/3 =

7/24 - 8/24 = -1/24

5 0
2 years ago
Read 2 more answers
PLEASE HELP ASAP 25 PTS + BRAINLIEST TO RIGHT/BEST ANSWER
Sunny_sXe [5.5K]

Answer:

The answer is  -4.

Step-by-step explanation:

Because the 4 x 4 is 16

4 0
3 years ago
A triangle has angle measurements of 56°, 54°, and 70°. What kind of triangle is it?
alexira [117]

Answer:

Right, I am an idiot so i might be wrong

Step-by-step explanation:

Every triangle has three angles which sum to 180 degrees.

There are three types of triangles based on the measures of its angles.

Right Triangle - Has one 90 degree angle

Acute Triangle - All angles less than 90 degrees

Obtuse Triangle - One angle greater than 90 degrees

In this example we are given 2 angles and must find the measure of the 3rd.

a + 56 + 34 = 180

a + 90 = 180

a = 90

Therefore, it is a Right Triangle.

8 0
3 years ago
A blimp is providing aerial television views of a football game. The television camera sights the stadium at a 7 degree angle of
levacccp [35]
The line of sight is the hypotenuse of a right triangle with short leg 400 m, 90 degree angle where the short leg meets the ground, an 83 degree angle at the top, and a 7 degree angle across from the right angle on the ground. Because this 7 degree angle is an alternate interior angle with the angle of depression, they are the same degree measure. Looking for the hypotenuse, we use the sin ratio: sin (7) = 400/x.

8 0
3 years ago
Find the area lying outside r=6cos(theta) and inside r=3+3cos(theta)
Sloan [31]
The area bounded by the 2 parabolas is A(θ) = 1/2∫(r₂²- r₁²).dθ between limits θ = a,b... 

<span>the limits are solution to 3cosθ = 1+cosθ the points of intersection of curves. </span>
<span>2cosθ = 1 => θ = ±π/3 </span>

<span>A(θ) = 1/2∫(r₂²- r₁²).dθ = 1/2∫(3cosθ)² - (1+cosθ)².dθ </span>
<span>= 1/2∫(3cosθ)².dθ - 1/2∫(1+cosθ)².dθ </span>
<span>= 9/8[2θ + sin(2θ)] - 1/8[6θ + 8sinθ +sin(2θ)] .. </span>
<span>.............where I have used ∫(cosθ)².dθ=1/4[2θ + sin(2θ)] </span>
<span>= 3θ/2 +sin(2θ) - sin(θ) </span>

<span>Area = A(π/3) - A(-π/3) </span>
<span>= 3π/6 + sin(2π/3) -sin(π/3) - (-3π/6) - sin(-2π/3) + sin(-π/3) </span>
<span>= π.</span>
7 0
3 years ago
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