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3 years ago

In calculating one variable statistics you find the standard deviation to be equal to zero

1 answer:

6 0

We can conclude that All the data points are exactly the same. When we calculate one variable statistic and we find that the standard deviation is equal to zero most likely that we can conclude is that all the data points will be exactly the same.

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66.

Naddik [55]

Answer: 530.66 units²

<u>Step-by-step explanation:</u>

$Area_{(circle)}=\pi r^2\qquad and\qquad r=\dfrac{diameter}{2}\\\\\\\implies Area_{(circle)}=\pi \bigg(\dfrac{diameter}{2}\bigg)^2\\\\\\\text{It is given that the diameter = 26:}\\A=\pi\bigg(\dfrac{26}{2}\bigg)^2\\\\\\.\quad =\pi \cdot 13^2\\\\\\.\quad =169\pi\\\\\\.\quad =\large\boxed{530.66}$

3 0

3 years ago

Can someone answers this question please master it correctly if it’s corect I will mark you brainliest

Inessa [10]

Answer:

4 people will be expected to win the prize

Step-by-step explanation:

Out of 15 people, 5 won a prize

5/15 = simplify into 1/3

1/3 = x/12 Cross multiply

3x = 12 Divide 3 on both sides

x = 4

<h3><u><em>Hope this helps!!!</em></u></h3><h3><u><em>:)</em></u></h3>

3 0

3 years ago

Plz help !!!!!!!!1

rosijanka [135]

Answer:

As outdoor temperatures increased, residents' electric bills increased.

Step-by-step explanation:

7 0

2 years ago

Suppose Kaitlin places $6500 in an account that pays 12% interest compounded each year.

Leya [2.2K]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 1 year}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &1 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 1}\implies A=6500(1.12)\implies A=7280 \\\\[-0.35em] ~\dotfill$

$\bf ~~~~~~ \textit{Compound Interest Earned Amount \underline{for 2 years}} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$6500\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases}$

$\bf A=6500\left(1+\frac{0.12}{1}\right)^{1\cdot 2}\implies A=6500(1.12)^2\implies A=8153.6$

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3 years ago

Convert 7/3 into a mixed number

antoniya [11.8K]

Answer:

2 1/3

Step-by-step explanation:

4 0

2 years ago