Answer:
the tent can hold 8.66 lb of water (or 240 in³ of it)
Step-by-step explanation:
assuming that the tent base is a rectangular area , and the vertical cross section is triangular , then the volume of the tent will be:
Volume of the tent = Area* height/2 = 60 in² * 8 in / 2 = 240 in³
assuming the density of water as 62.4 lb/ft³ then
mass of water = density * volume = 62.4 lb/ft³ * 240 in³ * (1 ft / 12 in)³ = 8.66 lb
then the tent can hold 8.66 lb of water (or 240 in³ of it)
<span> It would depend on the number of rows?
This is an arithmetic sequence and the sum of n terms is -->
n/2(2a+(n-1)d), where a is the first term and d is the common
difference. In this case a = 10, d =6
n/2(20+6(n-1)) = 3n^2 + 7n = ANSWER
n = number of rows
</span>
Answer:
x=2
Step-by-step explanation:
2x+10=14
2x=14-10
2x=4
x=4/2
x=2
Answer:
23.76
Step-by-step explanation:
Answer: choice A
Step-by-step explanation:
