Answer:
a)S= (1,2,3,4,5,6)
b) 1/6 or 16.67%
c) 1/3 or 33.33%
d) 5/6 or 83.33%
Step-by-step explanation:
a) Sample space is the list of all the possible sample in this its either tool 1,2,3,4,5 or 6
b) probability of selecting from tool 1 is equally likely to picking from any cutting tool therefore it
1/6 or 16.7%
c) probability of selecting from any tool is 16.7% so probability of selecting from 3 or 5 = 16.67% + 16.67% = 33.3%
d) if the part is not from tool 4 then its from tool 1, or tool 2 or tool 3 or tool 5 or tool 6 therefore its
1/6+1/6+1/6+1/6+1/6 = 5/6 or 8.33%
I would say the answer is 35.
Answer:
A. −4 + 4 = 0
Step-by-step explanation:
-4 + 4 = 0
4 - 4 = 0
So option A will be the answer
Answer: The concentration of X is
and the concentration of Y is
.
Step-by-step explanation:
Since we have given that
At 272 nm, absorbance = 0.215
At 327 nm, absorbance = 0.191
As we have given that
Compound X Compound Y
272 16400 3870
327 3990 6420
So, our equations becomes
![16400C_1+3870c_2=0.215\\\\3990C_1+6420C_2=0.191](https://tex.z-dn.net/?f=16400C_1%2B3870c_2%3D0.215%5C%5C%5C%5C3990C_1%2B6420C_2%3D0.191)
By solving these two equations, we get that
![C_1=7.13582\times 10^{-6}\\\\C_2=2.53159\times 10^{-5}](https://tex.z-dn.net/?f=C_1%3D7.13582%5Ctimes%2010%5E%7B-6%7D%5C%5C%5C%5CC_2%3D2.53159%5Ctimes%2010%5E%7B-5%7D)
Hence, the concentration of X is
and the concentration of Y is
.