Perimeter simply represents the sum of all side lengths of a shape. The length of the missing side of the ticket is 5 cm; the length of gold line on each ticket is 20 cm, and 2 bottles of gold ink are required to draw gold lines on 200 tickets.
I've added the image of the ticket as an attachment.
(a) The missing side length
From the attachment, the 4 unknown side lengths are equal. Represent this side length with L.
So, we have:
This gives
Collect like terms
Divide both sides by 4
(b) The length of the gold lines
There are 4 slant lines and the length of one of the slant lines is 5 cm (as calculated above).
So, the length of the gold line is:
(c) The number of gold ink bottles.
--- number of tickets
The length of all gold line in the 200 tickets is:
---- convert to meters
Given that:
--- 1 bottle for 20 m
The number of bottles (n) is:
Hence, 2 bottles of gold ink are enough.
Read more about perimeters at:
brainly.com/question/6465134
30/20= 1 and 10/20 in simplest form that is 1 and 1/2
The slope is 4. It's right there in the problem. The equation underneath that is y=mx + b. M, in this case 4 or 4/1 is the slope. And 5 is the y intercept or where the line crosses the y axis.
Answer:
Step-by-step explanation:
Given that you have n gold coins with one a fake that you know is slightly lighter.
Case I: n is odd. Separate the gold coins into two groups containing (n-1) on one side and one separate. Since n-1 is even split it into two equal sets and weigh on each side of the balance. If both balance then the one coin separate is the answer. Otherwise take the one which show higher weight and continue the process for n/2 also, if odd.
Case II: If n is even do the process as you did for n-1 in the previous explanation.
So minimum weighings required would be r where
For example, if 33 coins are there minimm weighings would be = 5 since
2^5<33<2^6
The length is 40 units. x3
