All categories

3 years ago

Answer for Answer Help me and ill help you.. Ill also mark you brilliant.. I really need help please!!

Mathematics

1 answer:

mixer [17]3 years ago

4 0

Answer:

- The point (7,0) is an x-intercept of the function

- The point (-3,0) is an x-intercept of the function

- As x -> - infinity, f(x) -> + infinity, and ss x -> infinity, f(x) -> + infinity

Step-by-step explanation:

You might be interested in

Identify the true and false statements about educational inequality in the united states.

USPshnik [31]

MONKEYS TWENTY CHARACTERS LONG!!

4 0

2 years ago

In the figure, a pair of parallel lines Is cut by a transversal. What kind of angle are angles A and C?

Sonbull [250]

Answer: Angles A and C are vertical angles.

Step-by-step explanation:

5 0

2 years ago

PLS HELP IM BEGGING U

expeople1 [14]

Answer:

answer is 57.

Step-by-step explanation:

Given

m<6= x - 8

m<7 = 2x - 7

We know

<6 + <7 = 180° [ being linear pair ]

x - 8 + 2x - 7 = 180°

3x - 15 = 180°

3x = 180° + 15°

3x = 195°

x = 195° / 3

x = 65°

Now

m<6= x - 8 = 65° - 8° = 57°

hope it helps :)

8 0

3 years ago

Write a polynomial that is a trinomial, has the coefficients 3 and 4, the variable x,

vladimir1956 [14]

Answer:

3x+4x+7

Step-by-step explanation:

First, a Trinomial consists of three terms.

so we have blank+blank+blank

Next we need to add the coefficients.

3+4+blank

Add the variables.

3x+4x+blank

And lastly, add the constant.

3x+4x+7

Good luck!

8 0

2 years ago

The probability of event A is x, and the probability of event B is y. If the two events are independent, which of these conditio

zzz [600]

If two events are independent, then

$Pr(A\cap B)=Pr(A)\cdot Pr(B)$ .

Use formulas for conditional probabilities:

$Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)},\\ \\ Pr(B|A)=\dfrac{Pr(A\cap B)}{Pr(A)}$ .

For independent events these formulas will be:

$Pr(A|B)=\dfrac{Pr(A\cap B)}{Pr(B)}=\dfrac{Pr(A)\cdot Pr(B)}{Pr(B)}=Pr(A),\\ \\ Pr(B|A)=\dfrac{Pr(A\cap B)}{Pr(A)}=\dfrac{Pr(A)\cdot Pr(B)}{Pr(A)}=Pr(B)$ .

Now in your case $Pr(A)=x,\ Pr(B)=y$ and $Pr(A|B)=x,\ Pr(B|A)=y, Pr(A\cap B)=x\cdot y$ .

This shows that the only correct choice is A.

5 0

3 years ago

Read 2 more answers