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3 years ago

What is the what's the value of 2 million

Mathematics

2 answers:

Marysya12 [62]3 years ago

7 0

The value of 2 million is 2,000,000

GuDViN [60]3 years ago

3 0

I don't understand is it property,worth or money

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Among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a ma

scoundrel [369]

Answer:

Step-by-step explanation:

Given that among 500 freshmen pursuing a business degree at a university, 315 are enrolled in an economics course, 213 are enrolled in a mathematics course, and 123 are enrolled in both an economics and a mathematics course.

From the above we find that

a) either economics of Math course is

$315+213-123 =405$

Out of 500 students 405 have taken either Math or Economics

Hence

c) student who have taken neither = $500-405 =95$

Exactly one course is either math or economics - both

= $405-123 = 282$

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3 years ago

If the 6th term of an A.p is 11and its first term is 1 find the common diferent

hram777 [196]

Answer:

$thank \: you$

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2 years ago

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PLS HURRY Point S is translated 5 units to the left and 12 units up to create point S'. Find the distance between point S and po

svet-max [94.6K]

Given:

Point S is translated 5 units to the left and 12 units up to create point S'.

To find:

The distance between the points S and S'.

Solution:

Point S is translated 5 units to the left and 12 units up to create point S'.

The diagram for the given problem is shown below.

From the below figure it is clear that the distance between the point S and S' is the height of a right triangle whose legs are 5 units and 12 units.

By Pythagoras theorem,

$Hypotenuse^2=Perpendicular^2+Base^2$

$SS'^2=(12)^2+(5)^2$

$SS'^2=144+25$

$SS'^2=169$

Taking square root on both sides.

$SS'=\sqrt{169}$

$SS'=13$

Therefore, the distance between S and S' is 13 units.

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3 years ago

In a stack of boards at a lumber yard, the 20th board counting from the top of the stack is immediately below the 16th board cou

Novosadov [1.4K]

Answer:

Step-by-step explanation:

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3 years ago

Help me? idk the answer :P

Alexus [3.1K]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\
\left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group}
\\\\
-------------------------------\\\\
$

$\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\
-------------------------------\\\\
\textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4$

$\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\
-------------------------------\\\\
\textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8}
\\\\\\
\cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}$

$\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9$

7 0

3 years ago