All categories

3 years ago

Explain why it is not reasonable to say that 4.23is less than 4.13

2 answers:

8 0

Its not a reasonable answer that 4.23 is less than 4.23 because if you look in the tenths space the number 2 in 4.23 is obviously greater than 1 in 4.13
<span />

Alina [70]3 years ago

7 0

It is not reasonable because the decimal placing on the 4.23 is greater then the one on 413. (2 is bigger then 1). When dealign with decimals it is important to remember that if the numbers before the decimal are the same for both numbers you need to look at the first decimal as though it's the first number. so we know 4 and 4 are the same. Next we look at the .23 and .13. We know that the number 2 is bigger then 1 so it's safe to say that 4.23 is larger then 4,13.

You might be interested in

Find the side in of point a to point c

vladimir1956 [14]

Step 1:

Calculate the measure of angle ∠ABC

$\angle DBC+\angle ABC=180(\text{ sum of angles on a straight line)}$ $\angle ABC=65^0$ $\begin{gathered} \angle DBC+\angle ABC=180 \\ \angle DBC+65^0=180^0 \\ \angle DBC=180^0-65^0 \\ \angle DBC=115^0 \end{gathered}$

From the triangle in the question,

$a=10\operatorname{km},c=15\operatorname{km},B=115^0$

Step 2:

Calculate the value of AB using the cosine rule below

$b^2=a^2+c^2-2\times a\times c\times\cos B$

By substituting the values, we will have

$\begin{gathered} b^2=a^2+c^2-2\times a\times c\times\cos B \\ b^2=10^2+15^2-2\times10\times15\times\cos 115^0 \\ b^2=100+225-300\times(-0.4226) \\ b^2=325+126.78 \\ b^2=451.78 \\ \text{Square root both sides} \\ \sqrt[]{b^2}=\sqrt[]{451.78} \\ b=21.26\operatorname{km} \end{gathered}$

Hence,

The distance of point A to point C is = 21.26km

3 0

1 year ago

PLEASE HELP THIS IS DUE IN 8 MINUTES <br> find the value of x

valentina_108 [34]

Answer: A. 8

Hope this helps

3 0

3 years ago

You want to buy some noodles. An 8-ounce package costs $2.88. A 14-ounce package costs

torisob [31]

Answer:

A 20-ounce package that costs $6.80 is the best buy

6 0

3 years ago

Many people who bought Z-Game gaming systems over the holidays have complained that the systems they purchased were defective. I

Bas_tet [7]

Answer:

The upper limit for the 95% confidence interval for the population proportion of defective gaming systems is 0.022

Step-by-step explanation:

Upper Limit for 95% Confidence Interval can be calculated using p+ME where

p is the sample proportion of defective gaming systems ( $\frac{18}{1200} = 0.015$ )

ME is the margin of error from the mean

and margin of error (ME) around the mean can be found using the formula

ME= $\frac{z*\sqrt{p*(1-p)}}{\sqrt{N} }$ where

z is the statistic of 95% confidence level (1.96)

p is the sample proportion ( $\frac{18}{1200}=0.015$

N is the sample size (1200)

Using the numbers we get:

ME= $\frac{1.96*\sqrt{0.015*0.985}}{\sqrt{1200} }$ ≈ 0.007

Then upper limit for the population proportion is 0.015+0.007 =0.022

4 0

4 years ago

What is x+4/5=2/3- x-3/6

natima [27]

$x+\frac{4}{5}=\frac{2}{3}-x-\frac{\not3^1}{\not6_2}\\\\x+\frac{4}{5}=\frac{2}{3}-x-\frac{1}{2}\\\\find\ LCD(\frac{4}{5};\ \frac{2}{3};\ \frac{1}{2})=2\times3\times5=30\\\\multiply\ both\ sides\ by\ LCD=30\\\\30x+30\cdot\frac{4}{5}=30\cdot\frac{2}{3}-30x-30\cdot\frac{1}{2}\\\\30x+6\cdot4=10\cdot2-30x-15\cdot1\\\\30x+24=20-30x-15$

$30x+24=5-30x\ \ \ \ |subtract\ 24\ from\ both\ sides\\\\30x=-19-30x\ \ \ \ \ |add\ 30x\ to\ both\ sides\\\\60x=-19\ \ \ \ \ |divide\ both\ sides\ by\ 60\\\\\boxed{x=-\frac{19}{60}}$

$\frac{x+4}{5}=\frac{2}{3}-\frac{x-3}{6}\\\\\frac{x+4}{5}=\frac{2\cdot2}{3\cdot2}-\frac{x-3}{6}\\\\\frac{x+4}{5}=\frac{4}{6}-\frac{x-3}{6}\\\\\frac{x+4}{5}=\frac{4-(x-3)}{6}\\\\\frac{x+4}{5}=\frac{4-x+3}{6}\\\\\frac{x+4}{5}=\frac{7-x}{6}\ \ \ \ |cross\ multiply$

$6(x+4)=5(7-x)\\\\6(x)+6(4)=5(7)-5(x)\\\\6x+24=35-5x\ \ \ \ \ |subtract\ 24\ from\ both\ sides\\\\6x=11-5x\ \ \ \ \ |add\ 5x\ to\ both\ sides\\\\11x=11\ \ \ \ \ |divide\ both\ sides\ by\ 11\\\\\boxed{x=1}$

6 0

4 years ago