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lidiya [134]
3 years ago
12

Unicorn Medicines, a pharmaceutical company based in the United States, has its research and development units spread across the

globe. These research and development units have lately not been receiving adequate financial support. Which of the following is typically the cause for such a situation?
A. Technical innovation leads to lower market segmentation and slower product obsolescence.
B. Most innovative ideas do not become successful new products.
C. The product development cycle in the pharmaceutical industry is short.
D. The cost associated with pharmaceutical research and development is low.
Business
1 answer:
Anna71 [15]3 years ago
7 0

<u>Answer:</u>

Unicorn Medicines, a pharmaceutical company based in the United States, has its research and development units spread across the globe. These research and development units have lately not been receiving adequate financial support.

(B) Most innovative ideas do not become a successful new product.

This is typically the cause for such a situation.

<u>Explanation:</u>

Whatever that comes to your mind will not necessarily take shape in reality. Success comes to that person who had the perspective of success in their mind and bring their thoughts to reality. Similarly, if we want to build a product for that, the innovative ideas that come to our mind should be applied and from that, the final product achieved will become desirable.  

Nowadays most of the innovative ideas do not become a successful new product thats why the financial supporters are hesitating to invest in any kind of research and development. So that's the reason why the research and development units have lately not been receiving adequate financial supporters.

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1 year ago
Each machine must be run by one of 19 cross-trained workers who are each available 35 hours per week. The plant has 10 type 1 ma
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Answer:

The Linear programming model is given as below

Profit Function: P=90X+120Y+150Z

Constraints:

2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

4X+6Y+5Z\leq 320

\dfrac{2X+2Y+Z}{40}\leq 10

\dfrac{3X+4Y+6Z}{40}\leq 6

\dfrac{4X+6Y+5Z}{40}\leq 8

\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

Explanation:

As the question is not complete, the complete question is found online and is attached herewith.

Let the number of product 1 to be produced is X, that of product 2 is Y and product 3 is Z

so  the maximizing function is the profit function which is given as

P=90X+120Y+150Z

Now as the number of hours in a week are 40 and there are a total of 10 type 1 machines so the total number of machine 1 hours are 40*10=400 hours

As from the given table product 1 uses 2 machine hours of machine 1, product 2 uses 2 machine hours of machine 1 and product 3 uses 1 hour of machine 1 so

2X+2Y+Z\leq 400

Now as the number of hours in a week are 40 and there are a total of 6 type 2 machines so the total number of machine 2 hours are 40*6=240 hours

As from the given table product 1 uses 3 machine hours of machine 2, product 2 uses 4 machine hours of machine 2 and product 3 uses 6 hour of machine 2 so

3X+4Y+6Z\leq 240

Now as the number of hours in a week are 40 and there are a total of 8 type 3 machines so the total number of machine 3 hours are 40*8=320 hours

As from the given table product 1 uses 4 machine hours of machine 3, product 2 uses 6 machine hours of machine 3 and product 3 uses 5 hour of machine 3 so

4X+6Y+5Z\leq 320

Now as the machine 1 is used as 2X+2Y+Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{2X+2Y+Z}{40}\leq 10

Now as the machine 2 is used as 3X+4Y+6Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{3X+4Y+6Z}{40}\leq 6

Now as the machine 3 is used as 4X+6Y+5Z in a week and the week is of 40 hours so the number of machines to be used are given as

\dfrac{4X+6Y+5Z}{40}\leq 8

Now the workers are available for 35 hours so the worker available at the machine 1 is given as

\dfrac{2X+2Y+Z}{35}

That of machine 2 is given as

\dfrac{3X+4Y+6Z}{35}

That of machine 3 is given as

\dfrac{4X+6Y+5Z}{35}

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\dfrac{2X+2Y+Z}{35}+\dfrac{3X+4Y+6Z}{35}+\dfrac{4X+6Y+5Z}{35}\leq 19

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2X+2Y+Z\leq 400

3X+4Y+6Z\leq 240

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\dfrac{4X+6Y+5Z}{40}\leq 8

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Answer:

$8,300

Explanation:

Calculation for what Elroy's incremental profit or loss would be if he chooses option 2 over option 1

Using this formula

Incremental Profit of option 2 over option 1= Profit from option 1 - Profit from option 2

Let plug in the formula

Incremental Profit of option 2 over option 1= ($3,600*3)-(3*$1,100 - $800)

Incremental Profit of option 2 over option 1= $10,800 - $2,500

Incremental Profit of option 2 over option 1= $8,300

Therefore Elroy's incremental profit or loss would be if he chooses option 2 over option 1 would be $8,300

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