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Aleonysh [2.5K]
3 years ago
7

Find the vertex, zero(s), and y-intercept of the graph of y = 2x2 + 8x – 90. A. Vertex: (–2,–98); zeros: (–5,0), (9,0) y-interce

pt: (0,–90) B. Vertex: (2,–98); zeros: (–5,0), (9,0) y-intercept: (0,90) C. Vertex: (2,98); zeros: (5,0), (–9,0) y-intercept: (0,–90) D. Vertex: (–2,–98); zeros: (5,0), (–9,0) y-intercept: (0,–90)
Mathematics
1 answer:
expeople1 [14]3 years ago
6 0

Answer:

vertex is (-2,-98)

zeros are (5,0) (-9,0)

y-intercept is (0,-90)

Step-by-step explanation:

we are given

y=2x^2+8x-90

Vertex:

we can use vertex formula

y=ax^2+bx+c

x=-\frac{b}{2a}

we can compare and find a,b and c

a=2 , b=8 and c=-90

so, we can plug it in formula

x=-\frac{8}{2\times 2}

x=-2

now, we can find y-value

y=2(-2)^2+8(-2)-90

y=-98

so, vertex is (-2,-98)

zeros:

we can set y=0

and then we can solve for x

y=2x^2+8x-90=0

we can factor it

2(x-5)(x+9)=0

x=5,x=-9

zeros are

(5,0) (-9,0)

y-intercept:

we can plug x=0 and find y

y=2(0)^2+8(0)-90

y=-90

So, y-intercept is (0,-90)


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