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AlladinOne [14]
4 years ago
14

Stuck on this Question !!

Mathematics
1 answer:
Veseljchak [2.6K]4 years ago
5 0
I got you bro the answer is c

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Given that ΔPQR is similar to ΔPTS, which statement MUST be true? A) m∠PST = m∠QPR B) m∠TPS = m∠RPQ C) m∠SPT = m∠PTS D) m∠PRQ =
skelet666 [1.2K]

Answer: B) m∠TPS = m∠RPQ


Step-by-step explanation:

Given that ΔPQR is similar to ΔPTS

We know that of two triangles are similar then their corresponding angles are equal in measure and corresponding sides are proportional.

Therefore, If ΔPQR is similar to ΔPTS, then

m∠TPS=m∠RPQ

m∠STP=m∠RQP

m∠PTS=m∠PQR

Therefore, from the given options, only B is the right options, i.e. m∠TPS = m∠RPQ


3 0
4 years ago
How to find the surface area of a hexagon?
shutvik [7]

Answer:

adding all the areas on the surface: the areas of the base, top, and lateral surfaces (sides) of the object.

Step-by-step explanation:

6 0
3 years ago
What is the positive slope of the asymptote of (y+11)^2/100-(x-6)^2/4=1? The positive slope of the asymptote is .
VladimirAG [237]

Answer:

the  positive slope of the asymptote = 5

Step-by-step explanation:

Given that:

\frac{(y+11)^2}{100} -\frac{(x-6)^2}{4} =1

Using the standard form of the equation:

\frac{(y-k)^2}{a^2}-\frac{(x-h)^2}{b^2}= 1

where:

(h,k) are the center of the hyperbola.

and the y term is in front of the x term  indicating that the  hyperbola opens up and down.

a = distance that indicates  how far above and below of the center the vertices of the hyperbola are.

For the above standard equation; the equation for the asymptote is:

y = \pm \frac{a}{b} (x-h)+k

where;

\frac{a}{b} is the slope

From above;

(h,k) = 11, 100

a^2 = 100

a = \sqrt{100}

a = 10

b^2 =4

b = \sqrt{4}

b = 2

y = \pm \frac{10}{2} (x-11)+2

y = \pm 5 (x-11)+2

y = 5x-53 , -5x -57

Since we are to find the positive slope of the asymptote: we have  

\frac{a}{b} to be  the slope in the equation  y = \pm \frac{10}{2} (y-11)+2

\frac{a}{b}  = \frac{10}{2}

\frac{a}{b}  = 5

Thus, the  positive slope of the asymptote = 5

8 0
3 years ago
jade and eliza went shopping at the mall Jade spent $10 more than five times and that Eliza spent jade spent a total of $150 wit
Anna71 [15]

Answer:

The equation that represent the given situation is 150=5x+10

The amount that Eliza spent was $28

Step-by-step explanation:

<u><em>The correct question is</em></u>

Jade and Eliza went shopping at a mall. Jade spent $10 more than 5 times the amount that Eliza spent. Jade spent a total of $150.With equation represents a given situation and what was the amount that Eliza spent

Let

x ---> the amount that Eliza spent

y ---> the amount that Jade spent

we know that

y=5x+10 ----> equation A

y=150 ---> equation B

substitute equation B in equation A

150=5x+10 ---> equation that represent the given situation

Solve for x

subtract 10 both sides

5x=150-10

5x=140

divide by 5 both sides

x=28

therefore

The  amount that Eliza spent was $28

3 0
3 years ago
Please help me find all the missing angles in the two problems
Yakvenalex [24]

the answer for the second problem is x=99 degrees and y= 261 degrees

dunno the first problem :/

3 0
3 years ago
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