A delivery truck weighs 5.5 tons before it is loaded with packages. Once the delivery truck is full of x packages it weighs 6.1
1 answer:
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Answer:
Q1
- cos 59° = x/16
- x = 16 cos 59°
- x = 8.24
Q2
BC is given 23 mi
<u>Maybe AB is needed</u>
- AB = √34² + 23² = 41 (rounded)
Q3
- BC² = AB² - AC²
- BC = √(37² - 12²) = 35
Q4
Let the angle is x
- cos x = 19/20
- x = arccos (19/20)
- x = 18.2° (rounded)
Q5
See attached
Added point D and segments AD and DC to help with calculation
- BC² = BD² + DC² = (AB + AD)² + DC²
<u>Find the length of added red segments</u>
- AD = AC cos 65° = 14 cos 65° = 5.9
- DC = AC sin 65° = 14 sin 65° = 12.7
<u>Now we can find the value of BC</u>
- BC² = (19 + 5.9)² + 12.7²
- BC = √781.3
- BC = 28.0 yd
<em>All calculations are rounded</em>
