Answer:
rate of the plane in still air is 33 miles per hour and the rate of the wind is 11 miles per hour
Step-by-step explanation:
We will make a table of the trip there and back using the formula distance = rate x time
d = r x t
there
back
The distance there and back is 264 miles, so we can split that in half and put each half under d:
d = r x t
there 132
back 132
It tells us that the trip there is with the wind and the trip back is against the wind:
d = r x t
there 132 = (r + w)
back 132 = (r - w)
Finally, the trip there took 3 hours and the trip back took 6:
d = r * t
there 132 = (r + w) * 3
back 132 = (r - w) * 6
There's the table. Using the distance formula we have 2 equations that result from that info:
132 = 3(r + w) and 132 = 6(r - w)
We are looking to solve for both r and w. We have 2 equations with 2 unknowns, so we will solve the first equation for r, sub that value for r into the second equation to solve for w:
132 = 3r + 3w and
132 - 3w = 3r so
44 - w = r. Subbing that into the second equation:
132 = 6(44 - w) - 6w and
132 = 264 - 6w - 6w and
-132 = -12w so
w = 11
Subbing w in to solve for r:
132 = 3r + 3(11) and
132 = 3r + 33 so
99 = 3r and
r = 33
Answer:
Step-by-step explanation:
are 1 and 2 answers becuas e if are 2
Let A = { 0 , 2 , 4 , 6 } , B = { 1 , 2 , 3 , 4 , 5 } , and C = { 1 , 3 , 5 , 7 } . Find { x ∣ x ∈ B or x ∈ C } .
EastWind [94]
Answer:
{1, 2, 3, 4, 5, 7}
Step-by-step explanation:
x in B or C is ...
B ∪ C = {1, 2, 3, 4, 5, 7}
Answer: 
Step-by-step explanation:
Having the following equation given in the exercise:
You can solve for "a" following this procedure:
1. You can apply the Subtraction property of equality and subtract 
from both sides of the equation:
2. Now you must subtract the terms on the left side of the equation. Notice that the Least Common Denominator is "d". Then:
3. Finally, you can apply the Multiplication property of equality and multiply both sides of the equation by "b". So, you get:
he has 0.6 km left to go, because if you take 1.7 - 0.9 it equals 0.6.
