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3 years ago

The answer I neeed it now

Mathematics

1 answer:

slava [35]3 years ago

5 0

Anser is B). Subtract smallest number

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Consider the proof. Given: In △ABC, BD ⊥ AC Prove: the formula for the law of cosines, a2 = b2 + c2 – 2bccos(A) Statement Reason

loris [4]

Solution: The missing reason in Step 8 is substitution of $x=c\cos (A)$ .

Explanation:

The given steps are used to prove the formula for law of cosines.

From step 5 it is noticed that our equation is

$a^2=b^2-2bx+c^2$ ..... (1)

From step 7 it is noticed that the value of $x$ is $c\cos (A)$ .

So by substituting $c\cos (A)$ for $x$ in equation (1) we get the equation of step 8, i.e.,

$a^2=b^2-2bc\cos (A)+c^2$

Hence, the missing reason in Step 8 is substitution of $x=c\cos (A)$ .

5 0

3 years ago

Read 2 more answers

Find the value of 216m³ - 8n³ if 6m - 2n=0 and mn=12

mestny [16]

Answer:

Step-by-step explanation:

Given that,

6m - 2n=0

=>6m=2n

=>n=3m [divide both side by 2]

& mn=12

Now,

216c - 8n³

= 216m³- 8(3m)³

=216m³- 8 .27m³

=216m³- 216m³

6 0

2 years ago

When the sum of 8 and a certain number is increased by 12, the result is the same as the product of 3 and the number. What is th

Roman55 [17]

ANSWER: The number is 10.
Hope this helps!!

I used the variable n as the number we needed to find. The equation was n + 8 + 12 = 3n

6 0

3 years ago

Scarlett is trying to find the height of a dam. She stands 90 meters away from the dam and records the angle of elevation to the

andrew-mc [135]

90(tan26) + 1.65 = about 107.7378 meters

3 0

3 years ago

There exist infinitely many common fractions $\frac{a}{b}$ , where $a > 0$ and $b > 0$ and for which $\frac{3}{5} < \fr

vredina [299]

Answer:

3/5 has the smallest denominator

Step-by-step explanation:

Question:

There exist infinitely many common fractions a/b , where a > 0 and b > 0 and for which 3/5 < a/b< 2/3. Of these common fractions, which has the smallest denominator? Express your answer as a common fraction.

Solution

A Common fraction is a rational number written in the form: a/b. Where a and b are both integers.

The denominator and numerator in this case are greater than zero. That is, they are non zeros.

The least common denominator (LCD) of two non- zero denominators is the smallest whole number that is divisible by each of the denominators.

To find the smallest denominator between 3/5 and 2/3, we would convert the fractions to equivalent fractions with a common denominator by finding their LCM (lowest common multiple).

When comparing two fractions with like denominators, the larger fraction is the one with the greater numerator and the smaller fraction is one with the smaller numerator.

In our solution after comparing, the smaller fraction would have the smallest denominator.

Find attached the solution.

3 0

3 years ago