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lubasha [3.4K]
4 years ago
9

The answer I neeed it now

Mathematics
1 answer:
slava [35]4 years ago
5 0
Anser is B). Subtract smallest number
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Answer:

<h2><u>ᎪꪀsωꫀᏒ </u></h2>

➪ (D) I and II

Step-by-step explanation:

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What statement is true about angles 1 and 2?​
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8 0
4 years ago
Rewrite the form In exponential form:<br> Log100 = x
andrey2020 [161]

Answer:

10^x=100

Step-by-step explanation:

You know how subtraction is the <em>opposite of addition </em>and division is the <em>opposite of multiplication</em>? A logarithm is the <em>opposite of an exponent</em>. You know how you can rewrite the equation 3 + 2 = 5 as 5 - 3 = 2, or the equation 3 × 2 = 6 as 6 ÷ 3 = 2? This is really useful when one of those numbers on the left is unknown. 3 + _ = 8 can be rewritten as 8 - 3 = _, 4 × _ = 12 can be rewritten as 12 ÷ 4 = _. We get all our knowns on one side and our unknown by itself on the other, and the rest is computation.

We know that 3^2=9; as a logarithm, the <em>exponent</em> gets moved to its own side of the equation, and we write the equation like this: \log_3{9}=2, which you read as "the logarithm base 3 of 9 is 2." You could also read it as "the power you need to raise 3 to to get 9 is 2."

One historical quirk: because we use the decimal system, it's assumed that an expression like \log1000 uses <em>base 10</em>, and you'd interpret it as "What power do I raise 10 to to get 1000?"

The expression \log100=x means "the power you need to raise 10 to to get 100 is x," or, rearranging: "10 to the x is equal to 100," which in symbols is 10^x=100.

(If we wanted to, we could also solve this: 10^2=100, so \log100=2)

6 0
3 years ago
Beatrice calculated the slope between two pairs of points.
kumpel [21]

Answer:

The answer in the procedure

Step-by-step explanation:

we know that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope between (-3, -2) and (1, 0)

m=\frac{0+2}{1+3}

m=\frac{2}{4}=\frac{1}{2}

Find the equation of the line

y-y1=m(x-x1)

with m and the point (1,0)

substitute

y-0=\frac{1}{2}(x-1)

y=\frac{1}{2}x-\frac{1}{2}

step 2

Find the slope between (-2, -1) and (4, 2)

m=\frac{2+1}{4+2}

m=\frac{3}{6}=\frac{1}{2}

Find the equation of the line

y-y1=m(x-x1)

with m and the point (4,2)

substitute

y-2=\frac{1}{2}(x-4)

y=\frac{1}{2}x-2+2

y=\frac{1}{2}x

<em>Compare the equation of the two lines</em>

The two lines are parallel, because their slope is the same, but are different lines

therefore

Beatrice's conclusion is incorrect

All of these points are not on the same line, because are different parallel lines

The slope between (-2,-1) and (1,0) is equal to \frac{1}{2}

8 0
4 years ago
Read 2 more answers
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