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vlabodo [156]
3 years ago
8

Suppose that a teacher agrees to pay a student 10​¢for every problem in this chapter that the student solves​ correctly, and fin

es the student 5​¢for every problem done incorrectly. If at the end of 30problems they do not owe each other any​ money, how many problems did the student solve​ correctly?
Mathematics
1 answer:
Andreas93 [3]3 years ago
5 0

Answer:  10

Step-by-step explanation:

Let x be the number of correct problems and y be the number of incorrect problems.

Given:  A teacher pays a student 10​¢ for every problem in this chapter that the student solves​ correctly, and fines the student 5 ¢ for every problem done incorrectly.

At the end of 30 problems they do not owe each other any​ money.

The by considering the given information we have the following equations :-

x+y=30-----(1)\\\\ 10x-5y=0------(2)

From (2), we have

5y=10x\\\\\Rightarrow\ y=2x

Put y=2x in (1)

x+2x=30\\\\\Rightarrow\ 3x=30\Rightarrow x=10

Then,  y=2(10)=20

Hence, the number of correct problems is 10 and the number of incorrect problems is 20.

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A ball is thrown straight out at 80 feet per second from an upstairs window that's 15 feet off the ground. Find the ball's horiz
Alex73 [517]

Answer:

Step-by-step explanation:

In order to find the horizontal distance the ball travels, we need to know first how long it took to hit the ground. We will find that time in the y-dimension, and then use that time in the x-dimension, which is the dimension in question when we talk about horizontal distance. Here's what we know in the y-dimension:

a = -32 ft/s/s

v₀ = 0 (since the ball is being thrown straight out the window, the angle is 0 degrees, which translates to no upwards velocity at all)

Δx = -15 feet (negative because the ball lands 15 feet below the point from which it drops)

t = ?? sec.

The equation we will use is the one for displacement:

Δx = v_0t+\frac{1}{2}at^2 and filling in:

-15=(0)t+\frac{1}{2}(-32)t^2 which simplifies down to

-15=-16t^2 so

t=\sqrt{\frac{-15}{-16} } so

t = .968 sec (That is not the correct number of sig fig's but if I use the correct number, the answer doesn't come out to be one of the choices given. So I deviate from the rules a bit here out of necessity.)

Now we use that time in the x-dimension. Here's what we know in that dimension specifically:

a = 0 (acceleration in this dimension is always 0)

v₀ = 80 ft/sec

t = .968 sec

Δx = ?? feet

We use the equation for displacement again, and filling in what we know in this dimension:

Δx = (80)(.968) +(0)(.968)^2 and of course the portion of that after the plus sign goes to 0, leaving us with simply:

Δx = (80)(.968)

Δx = 77.46 feet

5 0
3 years ago
Does this seem answer seem correct?
Blababa [14]
I mean I think so I’m not completely sure it’s a really hard question
5 0
3 years ago
Evaluate the numerical expression 24×5-41
Alinara [238K]
Start by multiplying 24*5 (PEMDAS)
24*5= 125
125-41=84
3 0
3 years ago
At HD Sport & Fitness gym, analysis shows that, as the demand of the gym, the number of members is 83 when annual membership
gayaneshka [121]

The price at which revenue is maximized is $ 157, and maximum annual revenue is $ 6751.

Since at HD Sport & Fitness gym, analysis shows that, as the demand of the gym, the number of members is 83 when annual membership fee is $ 17 per member and the number of members is 81 when annual membership fee is $ 24 per member, and the number of members and membership fee have a linear relationship, to determine at what membership price is the maximized revenue, and what is the maximum annual revenue, the following calculations must be performed:

  • 17 x 83 = 1411
  • 24 x 81 = 1944
  • 31 x 79 = 2449
  • 38 x 77 = 2926
  • 66 x 69 = 4554
  • 73 x 67 = 4891
  • 80 x 65 = 5200
  • 94 x 61 = 5734
  • 101 x 59 = 5959
  • 122 x 53 = 6466
  • 129 x 51 = 6579
  • 150 x 45 = 6750
  • 157 x 43 = 6751
  • 164 x 41 = 6724

Therefore, the price at which revenue is maximized is $ 157, and maximum annual revenue is $ 6751.

Learn more in brainly.com/question/11663530

4 0
2 years ago
A math class has 7 girls and 3 boys in the seventh grade and 3 girls and 9 boys in the eighth grade. The teacher randomly select
Bumek [7]

7th grade has 3 boy out of 10 students

 probability of picking a boy is 3/10

8th grade has 9 boys out of 12 students are boys

 probability of picking a boy is 9/12 reduced to 3/4

3/10 x 3/4 = 9/40 probability of picking 2 boys

4 0
3 years ago
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