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3 years ago

Which of the following functions grows at the same rate as ((x^4)+x)^(1/2)

Mathematics

1 answer:

neonofarm [45]3 years ago

6 0

Answer:

Step-by-step explanation:

(x⁴ + x)^½

As x approaches infinity, x⁴ becomes much larger than x. So:

(x⁴ + x)^½ ≈ (x⁴)^½ = x²

So x² grows at the same rate as (x⁴ + x)^½.

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Solve for "c."<br> a = b/(c-d)

8_murik_8 [283]

Answer:

ad+b

give me brilliant please

Step-by-step explanation:

c−d

Step 1: Multiply both sides by c-d.

ac−ad=b

Step 2: Add ad to both sides.

ac−ad+ad=b+ad

ac=ad+b

Step 3: Divide both sides by a.

ad+b

6 0

3 years ago

4w+15= -13<br><br> -12=n/2-6

Firlakuza [10]

Answer:

For the one including 4w the answer is - 7

The one with n/2 is - 12

Step-by-step explanation:

4w=-13-15

4w=-28

w=-7

Multiply by 2 on both sides

-24=n-12

-24+12=n

Always write it in the variables perspective.

n=-12

7 0

4 years ago

Please help asap!!!!

a_sh-v [17]

Answer:

Step-by-step explanation: 60

8 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

3 years ago

12+4(8x-1) please help

MakcuM [25]

Answer:

32x+8

Step-by-step explanation:

You’re welcome :)

6 0

3 years ago