Answer:
x = 6
Step-by-step explanation:
Let's solve your equation step-by-step.
6−8x=7x−10x−24
Step 1: Simplify both sides of the equation.
6−8x=7x−10x−24
6+−8x=7x+−10x+−24
−8x+6=(7x+−10x)+(−24)(Combine Like Terms)
−8x+6=−3x+−24
−8x+6=−3x−24
Step 2: Add 3x to both sides.
−8x+6+3x=−3x−24+3x
−5x+6=−24
Step 3: Subtract 6 from both sides.
−5x+6−6=−24−6
−5x=−30
Step 4: Divide both sides by -5.
−5x/-5 = -30 /-5
x=6
It would be D) (0,2) maximum
Hope this was helpful:)
Answer:
The answer is the third one
Step-by-step explanation:
I don't know the explanation I know the answer because I have that as my homework questionand my mom helped me I didn't know what she was saying but she said it is the third kne
Use this website https://nrich.maths.org/2281
Given the parameters in the diagrams, we have;
4. ∆ABC ≈ ∆DEF by ASA
5. UW ≈ XZ by CPCTC
6. QR ≈ TR by CPCTC
<h3>How can the relationship between the triangles be proven?</h3>
4. The given parameters are;
<B = <E = 90°
AB = DE Definition of congruency
<A = <D Definition of congruency
Therefore;
- ∆ABC ≈ ∆DEF by Angle-Side-Angle, ASA, congruency postulate
5. Given;
XY is perpendicular to WZ
UV is perpendicular to WZ
VW = YZ
<Z = <W
Therefore;
∆UVW ≈ ∆XYZ by Angle-Side-Angle, ASA, congruency postulate
Which gives;
- UW is congruent to XZ, UW ≈ XZ, by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
6. Given;
PQ is perpendicular to QT
ST is perpendicular to QT
PQ ≈ ST
From the diagram, we have;
<SRR ≈ <PRQ by vertical angles theorem;
Therefore;
∆QRP ≈ ∆TRS by Side-Angle-Angle, SAA, congruency postulate
Which gives;
- QR ≈ TR by Corresponding Parts of Congruent Triangles are Congruent, CPCTC
Learn more about congruency postulates here:
brainly.com/question/26080113
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