Answer:
19.5 miles per hour
Step-by-step explanation:
We need to change 20 minutes to hours
1 hours = 60 minutes
20 minutes * 1 hour/60 minutes = 1/3 hour
To find miles per hour we take the miles and divide by hours
6.5 miles
---------------- = 19.5 miles per hour
1/3 hours
Answer:
ΔGFE≈ΔJKL
Step-by-step explanation:
Let us name the players A,Dave,Zack,Paul,E and F
For the first position there are two candidades ( Zack / Paul )
For the second position there is only one candidate i.e. Dave
For the third place there will be 4 candidates (out of Zack and Paul - 1 as one of them is already taken for the first position and A, E and F total-4)
For the fourth place there will be 3 candidates ( out of the four available candidates in the 3rd place, one will be taken up for 3rd place )
For the fifth place there will be 2 candidates
Finally, for the last place there will be only one candidate left.
On multiplying the no. of available cadidates, we get 2 * 1 * 4 * 3 * 2 * 1 = 48 i.e. option (A)
Please mention minor spelling mistakes
For the second question:
Let the no of dotted marbles be 'x' and no of striped marbles be 'y'
then the equation will become as follows
(y+6)/x = 3
and
(x+6)/y = (2/3)
On solving the equations, we will get x = 10 and y = 24
Total balls = 10+24+6 = 40 (option E)
Answer 3 will be ) For the first edge, he can choose 3 paths
For the second edge he can choose 2 paths for each path of its first edge's path
For the third , he is bounded to move on the paths created by the first and the second edges hence 1 path for each path created by the first and the second edge together
It will be multiplication of all the possibilities of the paths of the three edges differently.........
i.e. 3 * 2 * 1 = 6
Answer:
Step-by-step explanation:
<u>Step 1: Set x to 4 and set y to -5</u>
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Answer:
Answer:
t=11,11 days
Step-by-step explanation:
F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating 
⇒ LnF=Kt+c,
; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), 
⇒
, so 
, now if F=130, t=? we have:
