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iren [92.7K]
3 years ago
9

PLEASE HELP

Mathematics
2 answers:
MAXImum [283]3 years ago
6 0

The answer is x=34 degrees.

Monica [59]3 years ago
5 0

The answer you are looking for is x=34.

Solution/Explanation:

First things first, we need to understand that the sum of the angles of a triangle is 180°. We can apply this fact for the problem.

So, that means that the sum of all of the angles of this triangle is 180°.

So, therefore, we can formulate an equation:

2x+20+2x-10+x=180.

So, we now have our expression.

Now, all we need to do is simplify it.

Combining similar-like terms,

2x+2x+x+20-10=180.

Simplifying it now,

5x+10=180.

Subtracting 10 from both sides of the equation,

5x+10-10=180-10.

5x=170.

Finally, dividing both sides by 5,

5x/5=170/5.

x=34.

So, therefore the final answer is x=34.

I hope that this has helped you. Enjoy your day, and take care!

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Distance between -23 & 17 = 40

Step-by-step explanation:

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Answer:

ASA  and AAS

Step-by-step explanation:

We do not know if these are right triangles; therefore we cannot use HL to prove congruence.

We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.

We are given that EF is parallel to HJ.  This makes EJ a transversal.  This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent.  We also know that ∠EGF and ∠HGJ are vertical angles and are congruent.  This gives us two angles and a non-included side, which is the AAS congruence theorem.

Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent.  Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.

4 0
3 years ago
Read 2 more answers
Suppose the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average
arsen [322]

Answer:

0.5372

Step-by-step explanation:

Given that the number of births that occur in a hospital can be assumed to have a Poisson distribution with parameter = the average birth rate of 1.8 births per hour.

Let X be the no of births in the hospital per hour

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There are 69120 total combinations.

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andrezito [222]

Answer:

0.58 = 58% probability she passes both courses

Step-by-step explanation:

We can solve this question treating the probabilities as a Venn set.

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Event B: She passes the second course.

The probability she passes the first course is 0.67.

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5 0
3 years ago
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