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Alchen [17]
3 years ago
5

The Periodic Table of elements is arranged by:

Chemistry
1 answer:
sergejj [24]3 years ago
5 0

Option D, atomic number is the correct answer

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A substance that will change shape to fit its container but has a definite volume is in a _____ phase of matter
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It’s a liquid because it can form any shape to fit container but the amount of liquid always stayed the same unless dropped some.
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Two substances with empirical formula HNO are hyponitrous acid (M = 62.04 g/mol) and nitroxyl (M = 31.02 g/mol).(d) When hyponit
astra-53 [7]

The cis and Trans-forms of hyponitrous acid are given below in the attached document.

Hyponitrous acid has the chemical formula H2N2O2 or HON=NOH. 62.028 g/mol is the molecular weight of it. Additionally, it can take either a trans or cis form. When dry, the trans-hyponitrous acid crystallizes into white, explosive particles. Additionally, it has a half-life of 16 days at 25oC at a pH 1-3 in aqueous solution and is a weak acid (pKa1=7.21, pKa2=11.54). It decomposes into nitrous oxide and water. It is incorrect to think of N2O as the anhydride of H2N2O2. However, even though cis acid is unknown, we can still get its sodium salts.

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2 years ago
Which celestial object is found in the Kuiper Belt?
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Beyond the planet Neptune is found a region filled with icy bodies. This region is known as the Kuiper Belt. This holds trillions of objects which is said to be remnants of the early solar system. The region contains comets and dwarf planets.
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Which is an example of an element? A) salt B) water C) silver D) electron
marusya05 [52]
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4 years ago
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Zippy decides he needs a drink to wash down the cold Pring Pongs. There are two 355 mL cans of Kookie Cola in the mini-bar.
Lady bird [3.3K]

20.7 Degree celsius is the temperature of Zippy's room.

Explanation:

The initial conditions of the kookie cola will be depicted by P1,V1 and T1.

P1= 36.5 psi or 2.4816 atm

V1= 355ml or 0.35 L

T1= 275.5K

The final conditions are given P2,V2 and T2

P2= 38.9 psi or 2.6469 atm

V2 = 355 ml or 0.35 L

also the solubility of the carbon dioxide does not change with temperature.

Applying the formula

P1VI/T1=P2V2/T2

since volume does not change and remains constant.

It can be written as:

P1/T1=P2/T2

= 2.4816/275.5=2.6469/T2

T2= 293.85 K

7 0
3 years ago
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