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3 years ago

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When 6.36 g of metallic chromium is heated with elemental chlorine gas, 19.37 g of a chromium chloride salt results. Calculate t

he empirical formula of the compound

1 answer:

kupik [55]3 years ago

3 0

Explanation:

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The density of ethanol, a colorless liquid that is commonly known as grain alcohol, is 0.798 g/ml. calculate the mass of 16.9 ml

sesenic [268]

Hey there!:

Density = 0.798 g/mL

Volume = 16.9 mL

Therefore:

Mass = density * volume

Mass = 0.798 * 16.9

Mass = 13.4862 g

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Find the mass in grams of 0.75 moles of magnesium (Mg).

Lady bird [3.3K]

Answer:

18.22874999999973

I recommend you to round the nearest 1 d.p

Explanation:

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3 years ago

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Molar mass of carbon

Taya2010 [7]

Answer: 12.011g/mol

Explanation: The molar mass of any element is usually stated at the bottom of periodic table (depending of your table anyways). Remember that the periodic table speaks to you in moles so every molar mass under the element is for 1 mole. By this I mean for example, 1 mole of Carbon = 12.011g of Carbon.

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3 years ago

How many Significant Figures does 105.60 have? *

nevsk [136]

Answer:

5 significant figures

Explanation:

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3 years ago

One solution has a formula C (n) H (2n) O (n) If this material weighs 288 grams, dissolves in weight 90 grams, the solution will

saw5 [17]

Explanation:

The given data is as follows.

Boiling point of water ( $T^{o}_{b}) = 100^{o}C$ = (100 + 273) K = 323 K,

Boiling point of solution ( $T_{b}) = 101.24^{o}C$ = (101.24 + 273) K = 374.24 K

Hence, change in temperature will be calculated as follows.

$\Delta T_{b} = (T_{b} - T^{o}_{b})$

= 374.24 K - 323 K

= 1.24 K

As molality is defined as the moles of solute present in kg of solvent.

Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

Let molar mass of the solute is x grams.

Therefore, Molality = $\frac{\text{weight of solute \times 1000}}{\text{molar mass of solute \times mass f solvent(g)}}$

m = $\frac{288 g \times 1000}{x g \times 90}$

= $\frac{3200}{x}$

As, $\Delta T_{b} = k_{b} \times molality$

$1.24 = 0.512 ^{o}C/m \times \frac{3200}{x}$

x = $\frac{0.512 ^{o}C/m \times 3200}{1.24}$

= 1321.29 g

This means that the molar mass of the given compound is 1321.29 g.

It is given that molecular formula is $C_{n}H_{2n}O_{n}$ .

As, its empirical formula is $CH_{2}O$ and mass is 30 g/mol. Hence, calculate the value of n as follows.

n = $\frac{\text{Molecular mass}}{\text{Empirical mass}}$

= $\frac{1321.29 g}{30 g/mol}$

= 44 mol

Thus, we can conclude that the formula of given material is $C_{44}H_{88}O_{44}$ .

4 0

3 years ago