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Andreyy89
3 years ago
13

How can a diagram help you know the exact answer

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
What type of diagram?
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The volume of the cone shown is 5 cubic inches. What is the height of a cone with the same base diameter but a volume of 10 cubi
Alisiya [41]

Answer:

The height of the big cone is double the one in the small cone

h2 = 2h1

Step-by-step explanation:

Given that:

  • The volume of the small cone: 5 cubic inches
  • The volume of the big cone: 10 cubic inches

As we know, the volume of a cone is as following:

V = (1/3)*area of the base*height

If the base diameter are unchanged => area of the base of the two cones are  unchanged and from the given information, the volume of the big cone is double the volume of the small cone. So the height of the big cone is double the one in the small cone

<=> h2 = 2h1

3 0
3 years ago
125% of blank is 85
nika2105 [10]

Answer:

68

125 percent (calculated percentage %) of what number equals 85? Answer: 68.

7 0
3 years ago
Read 2 more answers
In order to create the inverse of conditional statement "If p
____ [38]

Answer:

We just have to switch the positions of p and q so the answer is A.

8 0
3 years ago
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Please help my sister with this! 4. 3 gallons of paint are used to paint 16 wooden signs how much paint did you sign used betwee
Paul [167]

Answer:

<h2><em><u>.1etc</u></em></h2>

Step-by-step explanation:

It would be 16 divided by 3 and from the answer you get from that you should divide it by itself equaling infinite .111111111111etc

4 0
3 years ago
Daily-high temperature measurements for 40 consecutive days are recorded for a particular city. The mean daily-high temperature
Vesnalui [34]

Answer:

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

(D) P-val=0.021, fail to reject the null hypothesis

Step-by-step explanation:

1) Data given and notation  

\bar X=21.5 represent the mean for the temperatures

s=1.5 represent the sample standard deviation

n=40 sample size  

\mu_o =22 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is less than 22C, the system of hypothesis would be:  

Null hypothesis:\mu \geq 22  

Alternative hypothesis:\mu < 22  

If we analyze the size for the sample is > 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{21.5-22}{\frac{1.5}{\sqrt{40}}}=-2.108    

P-value

We can calculate the degrees of freedom like this:

df=n-1=40-1=39

Since is a one left tailed test the p value would be:  

p_v =P(t_{39}  

Conclusion  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the mean temperature actually its NOT significant less then 22 at 1% of signficance.  

The best option would be:

(D) P-val=0.021, fail to reject the null hypothesis

5 0
3 years ago
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