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Andreyy89
3 years ago
13

How can a diagram help you know the exact answer

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
What type of diagram?
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In the 2012 Paralympic Games, the total number of gold and silver medals won by Brazil was 35 The ratio of the number of gold me
Thepotemich [5.8K]

Answer:

the number of silver medals won by Brazil is 14

Step-by-step explanation:

The computation of the number of silver medals won by Brazil is shown below:

Given that

Total number of gold and silver medal wons by Brazil was 35

And, the ratio of number of gold medals to the number of silver medals be 3 : 2

Based on the above information

The number of silver medals won would be

= 35 × 2 ÷ (3 + 2)

= 35 × 2 ÷ 5

= 14

hence, the number of silver medals won by Brazil is 14

7 0
3 years ago
Why are and Iby 4<br>and - 1 zeroes of the polynomial p(x) <br>= 4² +3x-1?​
Serggg [28]

Answer:

- 1 = 16 + 3x - 1 \\ 3x = 16 - 1 + 1 \\  \frac{3x}{3} =  \frac{16}{3}  \\  x = 5.33

7 0
3 years ago
Does this graph show a function?explain how you know.
DiKsa [7]
The answer is B! It passes the vertical line test
5 0
3 years ago
7 What is the value of the expression -3x^2 y +4x when x = -4 and y = 2
love history [14]
<span> -3x^2 y +4x 
</span><span> =-3(-4)^2 (2) + 4(-4)
=-96-16
=-112</span>
7 0
3 years ago
Define fn : [0,1] --&gt; R by the
sasho [114]

Answer:

The sequence of functions \{x^{n}\}_{n\in \mathbb{N}} converges to the function

f(x)=\begin{cases}0&0\leq x.

Step-by-step explanation:

The limit \lim_{n\to \infty }c^{n} exists and converges to zero whenever \lvert c \rvert. But, if c=1 the sequence \{c^{n}\} is constant and all its terms are equal to 1, then converges to 1. Using this result, consider the sequence of functions \{f_{n}\} defined on the interval [0,1] by f_{n}(x)=x^{n}. Then, for all 0\leq x we have that \lim_{n\to \infty}x^{n}=0. Now, if x=1, then \lim_{n\to \infty }x^{n}=1. Therefore, the limit function of the sequence of functions is

f(x)=\begin{cases}0&0\leq x.

To show that the convergence is not uniform consider 0. For any n>1 choose x\in (0,1)  such that \varepsilon^{1/n}. Then

\varepsilon

This implies that the convergence is not uniform.

8 0
3 years ago
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