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gizmo_the_mogwai [7]
3 years ago
11

In ΔEFG, f = 1.2 inches, ∠E=55° and ∠F=109°. Find the length of e, to the nearest 10th of an inch.

Mathematics
1 answer:
Alekssandra [29.7K]3 years ago
3 0

Answer:

e = 1.04

Step-by-step explanation:

To find e, we apply the sine rule

e/sineE = f/sineF

e/sine55 = 1.2/sine109

e/0.8192 = 1.2/0.9455

0.9455e = 1.2 x 0.8192

e = 0.9830/0.9455

e = 1.0397

to nearest tenth = 1.04inch

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Step-by-step explanation:

Shown in the attachment.

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The distance around a meteor crater is 9,799 ft. Find the diameter of the crater. Use 22 7 for π.
madam [21]

Answer:

3118.7ft

Step-by-step explanation:

Given data

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What is the probability that you would obtain a sum of 7 or a sum of 11 on the first roll? (Rolling two dice.)
crimeas [40]

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5 0
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Please help with #12 im confused<br> that is the key but i dont get it
Svetllana [295]

Given Equation

\boxed{ \tt \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})}

Step by step expansion:

\dashrightarrow \sf \: (8 \sqrt{3}  - 2 \sqrt{2} )(8 \sqrt{3}   + 2 \sqrt{2})

\\  \\

\dashrightarrow \sf \: (8 \sqrt{3})^{2}  - (2 \sqrt{2}  {)}^{2}

Reason:

(a + b)(a - b) = a²- b²

\\  \\

\dashrightarrow \sf \: (8 {}^{2}  \times  { \sqrt{3} }^{2} )- (2 \sqrt{2}  {)}^{2}

\\  \\

\dashrightarrow \sf \: (64  \times 3 ) - (2 \sqrt{2}  {)}^{2}

\\  \\

\dashrightarrow \sf \: (64  \times 3 ) - (2 {}^{2} \times   \sqrt{2}  {}^{2}  {)}

\\  \\

\dashrightarrow \sf \: 192- 8

\\  \\

\dashrightarrow \sf \: 184

\\  \\

~BrainlyVIP ♡

4 0
2 years ago
Read 2 more answers
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