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3 years ago

Can someone please help meee?

Mathematics

1 answer:

qwelly [4]3 years ago

6 0

Answer:

Step-by-step explanation:

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N divided Into 8 is what

Goryan [66]

Answer:

$\frac{N}{8}$

Dividing is the same as putting numbers into a fraction. This is N/8. We don't get the answer until we figure out what N is equal to.

7 0

3 years ago

if the total angle of a triangle is 180 A- 43 1/2 B-5x C-26.5 and the started value is 20 what is X?

ValentinkaMS [17]

Answer:

x= 20.05 degree

180= 43.25+36.50+5x

180= 79.75+5x

5x=180-79.75

5x=100.25

x=20.25

ANGLE B= 100.25

3 0

3 years ago

Solve for X<br><br> B. X<br> X<br> 152

krok68 [10]

Answer:

Step-by-step explanation:

180 - 152 = 28

2x + 28 = 180

2x = 152

x = 76

3 0

3 years ago

The histogram below shows cell phone data usage in megabytes (Mb).

k0ka [10]

Answer:

200 – 300 Mb

Step-by-step explanation:

Becuse 200-300 is in the middle of the graph its a really simple qustion

4 0

3 years ago

The rate of growth of profit (in millions) from an invention is approximated by Upper P prime (x )equals x e Superscript negati

Alecsey [184]

Answer:

The function is $P(x) = \frac{1}{2} e^{-x^2} +0.016$

Step-by-step explanation:

From the question we are told that

The rate of growth is $P'(x) = xe^{x} - x^2$

The total profit is $P(2) =$ $25,000

The time taken to make the profit is $x = 2 \ years$

From the question

$P'(x) = xe^{-x^2}$ is the rate of growth

Now here x represent the time taken

Now the total profit is mathematically represented as

$P(x) = \int\limits {P'(x)} \, = \int\limits {xe^{-x^2}} \,$

So using substitution method

We have that

$u = - x^2$

$du = 2xdx$

$p(x) = \int\limits {\frac{1}{2} e^{-u}} \, du$

$p(x) = {\frac{1}{2} [ e^{-u}} +c ]$

$p(x) = {\frac{1}{2} e^{-x^2}} + \frac{1}{2} c$ recall $u = - x^2$ and let $\frac{1}{2} c = Z$

At x = 2 years

$P(x) =$ $25,000

Since the profit rate is in million

$P(x) =$ $25,000 = $\frac{25000}{1000000} =$ $0.025 millon dollars

$0.025 = {\frac{1}{2} e^{-2^2}} + Z$

=> $Z = 0.025 - {\frac{1}{2} e^{-2^2}}$

$Z = 0.016$

So the profit function becomes

$P(x) = \frac{1}{2} e^{-x^2} +0.016$

5 0

3 years ago