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barxatty [35]
4 years ago
14

A}20b}28C}23D}26i need some help asap

Mathematics
1 answer:
DaniilM [7]4 years ago
3 0
The answer would be 26 due to the fact that it’s just nearly above the 25 mark
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F(t)=100−4.9t2 help me
stiv31 [10]
-19.6 m/s
Do you need the math as well?
7 0
3 years ago
Solve for x and y 1/(x+yi) + 2/(x-yi) = 1+i
aliina [53]

Answer:

Step-by-step explanation:

x+i*y≠0 ==> x≠0 and y≠0

x-i*y≠0 ==> x≠0 and y≠0

We must exclude (0,0) as solution.

\dfrac{1}{x+i*y} +\dfrac{2}{x-i*y} =1+i\\\\\dfrac{1*(x-i*y)}{(x+i*y)(x-i*y)} +\dfrac{2*(x+i*y)}{(x-i*y)(x+i*y)} =1+i\\\\\\\dfrac{x-i*y+2x+2i*y}{x^2+y^2} =1+i\\\\3x+i*y=(1+i)(x^2+y^2)\\\\3x+i*y=(x^2+y^2)+i(x^2+y^2+i*(x^2+y^2)\\\\\left\{\begin{array}{ccc}3x&=&x^2+y^2\\y&=&x^2+y^2\\\end {array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&3x\\3x&=&x^2+9x^2\\\end {array}\right.\\\\\\\left\{\begin{array}{ccc}y&=&3x\\x(10x-3)&=&0\\\end {array}\right.\\\\

\left\{\begin{array}{ccc}x&=&0\\y&=&0\\\end {array}\right.\ (to\ exclude) \ or \ \left\{\begin{array}{ccc}x&=&\dfrac{3}{10}\\\\y&=&\dfrac{9}{10}\\\end {array}\right.\\\\Sol=\{(\dfrac{3}{10},\dfrac{9}{10})\}\\

4 0
3 years ago
The legs of an isosceles triangle are 7cm longer than the base. Find the legs if the perimeter of the triangle is 38cm.
irina [24]

The legs of an isosceles triangle are 7cm longer than the base. Find the legs if the perimeter of the triangle is 38cm.

(38 - 7 - 7) : 3 = <em>8 cm  (base)</em>

8 + 7 =

<h2><u><em>15 cm ( Legs)</em></u></h2>

check

8 + 15 + 15 = 38

the answer is good

3 0
2 years ago
Read 2 more answers
7/10 + 7/100 = 77/100
tensa zangetsu [6.8K]

Answer:

what I'm am supposed to be answering

5 0
2 years ago
Read 2 more answers
A screening test for a newly discovered disease is being evaluated for its performance as a screening test. In order to determin
Elena-2011 [213]

Answer:

- Sensitivity = 62.7 %

- specificity = 74.9 %

- positive predictive value = 45.2 %

- negative predictive value = 85.9 %

- Accuracy of the test = 71.9 %

Step-by-step explanation:

Given the data in th question;

                                 CONDITION POSITIVE    CONDITION NEGATIVE   TOTAL

TEST POSITIVE                   42                                       51                            93

TEST NEGATIVE                 25                                      152                          177

TOTAL                                  67                                     203                         270

so; A=42, B=51, C=25 and D=152

Sensitivity = [A / ( A + C) ]×100= [42 /( 42 + 25)]×100 = [42 / 67] 100=

Sensitivity = 62.7 %

specificity = [D / ( D + B) ]×100= [152 /( 152 + 51)]×100 = [152 / 203] 100=

specificity = 74.9 %

positive predictive value = [A / ( A + B) ]×100 = [42 /( 42 + 51)]×100 =[42/93] 100

positive predictive value = 45.2 %

negative predictive value =  [D / ( D + C) ]×100 = [152 /( 152 + 25)]×100 =[152/177] 100

negative predictive value = 85.9 %

Accuracy of the test = [A + D / ( A+B+C+D)] =  [42 + 152 / ( 42+51+25+152)]

= [ 194 / 270 ]

Accuracy of the test = 71.9 %

3 0
3 years ago
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