30= 3*10
30= 3*2*5
48= 12*4
48= 3*4*4
48= 3*2*2*2*2
60= 3*20
60= 3*10*2
60= 3*2*5*2
The GCF is 3*2 because all 3 numbers contain a 3 and a 2 in their prime factorizations.
Final answer: 6
Answer:
3,327.9
Step-by-step explanation:
now: 1996.67
original: 3,327.9
1996.67/.6 = 3,327.9
Answer:
The test is not significant at 5% level of significance, hence we conclude that there's no variation among the discussion sections.
Step-by-step explanation:
Assumptions:
1. The sampling from the different discussion sections was independent and random.
2. The populations are normal with means and constant variance
There's no variation among the discussion sections
There's variation among the discussion sections

Df Sum Sq Mean sq F value Pr(>F)
Section 7 525.01 75 1.87 0.99986
Residuals 189 7584.11 40.13
Test Statistic = 

Since our p-value is greater than our level of significance (0.05), we do not reject the null hypothesis and conclude that there's no significant variation among the eight discussion sections.
Answer:
1. (7+3)/2
2. 6, 3
3. 5/6
4. 500, 4000
Step-by-step explanation:
1. We are adding 7 and 3 so use the plus sign, THEN we divide by 2
Because we are adding first, put parentheses
(7+3)/2
2. Nearest whole means whole number (so basically no decimal)
5.823 --> 6 (because 8 is closer to 10 than 0)
3.147 --> 3 (because 1 is closer to 0)
3. 1/3+1/2
Find a common difference, which is 6
Multiply to get 6
1/3*2= 2/6
1/2*3=3/6
3+2=5/6 (when adding keep denominator the same)
4. There are 100 centimeters in a meter
5*100= 500 centimeters
There are 1000 grams in a kilogram
4*1000= 4000 grams
Hope this helps, lemme know if somethings still unclear!!
Answer:

Step-by-step explanation:
This question is illustrated using the attachment and will be solved using cosine formula

<em>Let the strawberry side be s, the Green beans be b and the pumpkins be p.</em>
<em />
The cosine formula in this case is:

Where



The equation becomes



Collect Like Terms


Using quadratic formula:

Where







or 
or 
or 
But length can not be negative.
So:
