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andrew11 [14]
4 years ago
8

A patient is to take 60mg of an antibiotic on day 1 ,take 45 mg on days 2 and 3 ,take 30mg on day 4 and 5 and take 15 mg on day

6 and 7. How many total mg will the patient take ?
Mathematics
2 answers:
-Dominant- [34]4 years ago
7 0

This is basically simple addition.

1st day=60

2nd day=45

3rd day=45

4th day=30

5th day=30

6th day=15

7th day=15

So, we solve the equation; 60+45+45+30+30+15+15=240

Your final answer; the patient will take 240mg of antibiotics.

Hope that helps, please rate.

Amanda [17]4 years ago
6 0

60+45+45+150

150+30+30=210

210+15+15=240

The patient will take 240 total mg

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the area of the exposed circle is

A =\pi a^2

the rate of change of this area can be, (using chain rule)

\frac{dA}{dt} = 2 \pi a \frac{da}{dt} we can call this Eq(2)

what we are really concerned about is how a changes as the punch is being poured into the bowl i.e \frac{da}{dh}

So we need another formula: Using the property of hemispheres and pythagoras theorem, we can use:

r = \frac{a^2 + h^2}{2h}

and rearrage the formula so that a is the subject:

a^2 = 2rh - h^2

now we can derivate a with respect to h to get \frac{da}{dh}

2a \frac{da}{dh} = 2r - 2h

simplify

\frac{da}{dh} = \frac{r-h}{a}

we can put this in Eq(1) in place of \frac{da}{dh}

\frac{da}{dt} = \frac{r-h}{a} . \frac{dh}{dt}

and since we know \frac{dh}{dt} = 1.5

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and now we use substitute this \frac{da}{dt}. in Eq(2)

\frac{dA}{dt} = 2 \pi a \frac{(r-h)(1.5)}{a}

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r = 5cm

h = 2cm from the question

\frac{dA}{dt} = 3 \pi (5-2)

\frac{dA}{dt} = 9 \pi cm/s// or//\frac{dA}{dt} = 28.27 cm/s

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