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Anna007 [38]
3 years ago
14

You are painting the outside of a 28 foot fence that goes around a square garden there are four equal sections you have painted

1/2 of one section what fraction of the job have you completed
Mathematics
1 answer:
Usimov [2.4K]3 years ago
6 0
4/2 or or 1/2 the job in other words 28 ft
You might be interested in
3 times the first of three consecutive odd integers is 3 more than twice the third? what is the third integer
fenix001 [56]

Answer:

15

Step-by-step explanation:

The difference between consecutive integers is 1.

The difference between consecutive odd integers is 2.

Let the smallest odd integer be x.

Then the next greater one is x + 2. The greatest one is x + 4.

"3 times the first" is 3x

"twice the third" is 2(x + 4)

"3 times the first of three consecutive odd integers is 3 more than twice the third"

3x = 2(x + 4) + 3

3x = 2x + 8 + 3

x = 11

The smallest integer is 11.

x + 4 = 11 + 4 = 15

The greatest one is 15.

4 0
3 years ago
At a school fair, students were challenged to hit one of the small congruent circles on the large rectangular board with a ball.
shtirl [24]

Answer:

~4.7%

Step-by-step explanation:

Area of the rectangle: 35*52=1820

Area of 1 small circle: A=πr2=π·32≈28.27433

28.27433*3=84.82299

84.82299/1820=0.04660603846

Therefore, about 4.7%

6 0
3 years ago
What is a estimate of 7/10 times 16 uses a benchmark fraction
Annette [7]
The answer is 11 1/5
6 0
3 years ago
Read 2 more answers
Hello i need help with these questions asap!!
makvit [3.9K]

We use direct proportionality:

360⁰......Pi×R² (full circle)

120⁰.......x

x=120×pi×R²/360=pi×R²/3

x=pi×4²/3=16.76mi²

A=3×pi cm², for an angle of 2×pi/3=120⁰

In a similar way we compute the area of the full circle:

360.........x

120..........3×pi

x=3×pi×360/120=9×pi=3²×pi.

Thus the radius is 3cm.

3 0
3 years ago
The center of mass is defined as a point on the straight line between two objects with masses m1 and m2 such that . What are the
STatiana [176]
Let the point be P, and the masses be located at P1 and P2.

The centre of mass is such that the moments of masses m1 and m2 exert an equal moment at the point P,
and the distance P1P2=d
namely,

m1(mPP1)=m2(mPP2)
The distance of the centre of mass from m1 is therefore
d1=d*m2/(m1+m2)
Similarly, the distance of the centre of mass from m2 is
d2=d*m1/(m1+m2)
5 0
3 years ago
Read 2 more answers
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