The vector AB is not related with the vector CD as k is not the same for each pair of components.
<h3>Are two vectors similar?</h3>
In this question we must prove if the vector AB is a multiple of the vector CD, that is:
![\overrightarrow{AB} = k \cdot \overrightarrow {CD}](https://tex.z-dn.net/?f=%5Coverrightarrow%7BAB%7D%20%3D%20k%20%5Ccdot%20%5Coverrightarrow%20%7BCD%7D)
![\vec B - \vec A = k \cdot [\vec D - \vec C]](https://tex.z-dn.net/?f=%5Cvec%20B%20-%20%5Cvec%20A%20%3D%20k%20%5Ccdot%20%5B%5Cvec%20D%20-%20%5Cvec%20C%5D)
(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]
(- 1, 1) = k · (- 3, - 1)
Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.
To learn more on vectors: brainly.com/question/13322477
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First bring them to common denominator.
Answer:
Incorrect
Step-by-step explanation:
The fraction of 6/12 all squared gives 36/144 36/36 and 144/36 reduces to 1/4.
Divide 636 / 12 which equals 53 ?