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3 years ago

Need Help! Offering 10 points!

Mathematics

1 answer:

KengaRu [80]3 years ago

6 0

Answer:

Step-by-step explanation:

Draw it out first! It may help! If not ask again and I will help

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Find the measure of angle b

hammer [34]

Answer:

38 degrees

180-142

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3 years ago

Two resorts advertise an average temperature of 75°F during the peak season. A travel agent researches the daily high temperatur

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ans C. the average temperature at the two resorts is about the same, but the range of temperature is different

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3 years ago

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In the past year Jenny watched 44 movies that she thought were very good. She watched 55 movies over the whole year. Of the movi

igomit [66]

To solve this problem, we must divide the number of movies that Jenny thought were very good by the total number of movies she watched. This is because we are finding a percentage, which represents a part out of a whole that have a factor, which in this case is very good movies. First, we begin by dividing 44/55. Then, we realize that both the numerator and the denominator are divisible by 11, so if we divided them both by 11 that would simplify the fraction.

44/55 = 44/11 / 55/11 = 4/5

Next, we can now easily divide our simplified fraction.

4/5 = 0.8

Finally, we must multiply by 100, because a percentage is a portion of 100 (the total is 100%). This is equivalent to moving the decimal point two places to the right.

0.8 * 100 = 80%

Therefore, Jenny thinks that 80% of the movies she watched this year were very good.

Hope this helps!

7 0

3 years ago

Given: is an angle bisector of ∠JMK Prove: m

astraxan [27]

Answer:

An angle bisector is a line passing through the vertex of the angle that cuts the angle into two equal smaller angles.

Given: MN is angle bisector,

then

$\angle JMN \cong \angle NMK$ ....... [1]

Congruent angles are two or more angles that have the same measure.

then;

by definition of congruent angles

[1]⇒ $m\angle JMN = m\angle NMK$ ......[2]

By the Angle addition postulates states that if M is in the interior of ∠JMK then,

$m\angle JMN+m\angle NMK =m\angle JMK$ ......[3]

Now, by substitution property ; substitute the equation [2] in [3] we get;

$m\angle JMN+m\angle JMN =m\angle JMK$ ......[4]

Like terms terms whose variables are the same

Combine like terms in equation [4] we get

$2 \cdot m\angle JMN=m\angle JMK$ ......[5]

Division property of equality states that you divide the same number to both sides of an equation.

Divide by 2 to both sides in equation [5] , we get

$m\angle JMN= \frac{1}{2} m\angle JMK$

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3 years ago

Geraldine is asked to explain the limits on the range of an exponential equation using the function f(x) = 2^x. She makes these

GalinKa [24]

General Idea:

Domain is the values of x which gives a defined output to the function, and Range is the values of y that we get by substituting domain values of x. For the function f(x) = a^x, where a > 0, the domain will be all real numbers and range will be all values greater than 0. That is the graph will be very close to x-axis but will never touch it.

Applying the concept:

From the attached table, we can notice that as x increases infinitely, the y-values are continually doubled for each single increase in x and as x decreases infinitely, the y-values are continually halved for each single decrease in x.

Option 1: "Statement 1 is incorrect because the y-values are increased by 2, not doubled".

Option 1 is INCORRECT because Statement 1 is TRUE & CORRECT.

Option 2: "Statement 2 is incorrect because the y-values are doubled, not halved".

Option 2 is INCORRECT because Statement 2 is TRUE & CORRECT.

Option 3: "The conclusion is incorrect because the range is limited to the set of the integers"

Option 3 is INCORRECT because, the range will be always greater than 0, because irrespective of how many times y is halved for each single decrease in x, the y will still be a positive fraction and won't be a negative.

Option 4: "The conclusion is incorrect because the range is limited to the set of positive real numbers"

Option 4 is CORRECT because y value will be positive irrespective of whatever x we substitute in the function.

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3 years ago

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