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zimovet [89]
3 years ago
7

Which number is the smallest? A) 1.28 x 10-4 B) 2.85 x 10-6 C) 3.24 x 10-5 D) 5.48 x 10-8

Mathematics
2 answers:
Murljashka [212]3 years ago
8 0
D) because it has 10^-8 which makes the number least
Charra [1.4K]3 years ago
4 0
I hope this helps you

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Which of the following is the simplified form of the seventh root of x times the seventh root of x times the seventh root of x ?
Studentka2010 [4]
When multiplying numbers of the same base , we add the powers.
Example:
2^2 * 2^3 = 2^(2+3) = 2^5

For the givens:
The seventh root of x can be written as x^(1/7)
Now, we need to multiply x^(1/7) by x^(1/7) by x^(1/7)
These numbers have the same base which is "x", therefore, we will just add the power.
This means that:
x^(1/7) * x^(1/7) * x^(1/7) = x^(1/7 + 1/7 + 1/7) = x^(3/7)

Therefore, the correct choice is the first one: x^(3/7)

5 0
3 years ago
Find the are of a parallelogram that has a base of 7 1/2 and a height of 5 2/7
Amiraneli [1.4K]
Use the formula for the area of a parallelogram:

\sf A=bh

Plug in what we know:

\sf A=(7\dfrac{1}{2})(5\dfrac{2}{7})

Convert both of them into improper fractions. We do this by multiplying the denominator to the whole number, adding it to the numerator, which becomes our new numerator, and we keep the denominator the same:

\sf A=(\dfrac{15}{2})(\dfrac{37}{7})

Now multiply the numerators and denominators together:

\sf A=\dfrac{15}{2}\cdot\dfrac{37}{7}\rightarrow\dfrac{15\cdot 37}{2\cdot 7}\rightarrow\dfrac{555}{14}

Convert it back into a mixed number. 14 goes into 555 thirty-nine times. 14 * 39 = 546. 555 - 546 = 9. So we have 39 wholes and 9 left over, or:

\sf 39\dfrac{9}{14}

So this is the area of the parallelogram.
6 0
3 years ago
5. In this diagram, lines AC and DE are parallel,
zhannawk [14.2K]

The length of side DE is 3cm

<h2 /><h3>Parallel line</h3>

Since the line AC is equivalent to DE, hence AC = DE

To get the length of DE, we will need to get the length oF AC using the Pythagoras theorem:

Given the following parameters

Hypotenuse = 5

Opposite = 4

Required

Adjacent side

Substitute the given parameters into the formula of Pythagoras theorem.

AC² = 5² - 4²

AC² = 25 - 16

AC² = 9

AC = 3

Hence the length of side DE is 3cm

Learn more on Pythagoras theorem here: brainly.com/question/12306722

8 0
3 years ago
The area of ABED is 49 square units. Given AGequals9 units and ACequals10 ​units, what fraction of the area of ACIG is represent
stiks02 [169]

Answer:

The fraction of the area of ACIG represented by the shaped region is 7/18

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

In the square ABED find the length side of the square

we know that

AB=BE=ED=AD

The area of s square is

A=b^{2}

where b is the length side of the square

we have

A=49\ units^2

substitute

49=b^{2}

b=7\ units

therefore

AB=BE=ED=AD=7\ units

step 2

Find the area of ACIG

The area of rectangle ACIG is equal to

A=(AC)(AG)

substitute the given values

A=(9)(10)=90\ units^2

step 3

Find the area of shaded rectangle DEHG

The area of rectangle DEHG is equal to

A=(DE)(DG)

we have

DE=7\ units

DG=AG-AD=9-7=2\ units

substitute

A=(7)(2)=14\ units^2

step 4

Find the area of shaded rectangle BCFE

The area of rectangle BCFE is equal to

A=(EF)(CF)

we have

EF=AC-AB=10-7=3\ units

CF=BE=7\ units

substitute

A=(3)(7)=21\ units^2

step 5

sum the shaded areas

14+21=35\ units^2

step 6

Divide the area of  of the shaded region by the area of ACIG

\frac{35}{90}

Simplify

Divide by 5 both numerator and denominator

\frac{7}{18}

therefore

The fraction of the area of ACIG represented by the shaped region is 7/18

5 0
3 years ago
Tom's coach keeps track of the number of plays that Tom carries the ball and how many yards he gains. Select all the statements
Brums [2.3K]

Answer:The dependent variable is the number of plays he carries the ball.

The independent variable is the number of touchdowns he scores.

The dependent variable is the number of yards he gains.

These are the ones that you need to choose.

7 0
3 years ago
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