All categories

2 years ago

on a scale drawing, a tree is 6 3/4 inches tall. the scale factor is 1/20. find the height of the actual tree.

Mathematics

2 answers:

Hoochie [10]2 years ago

8 0

I think the answer is 15

Verdich [7]2 years ago

4 0

To solve this problem you could set up a proportion 1/20=6.75/x. Next you would use property of cross products to get 20*6.75=x. Just mulitply to solve you should get 135 inches. To find the answer in ft just divide by 12

You might be interested in

ALG II NEED HELP QUICK! Will mark the brainliest answer

lbvjy [14]

I think it’s the second one because The formula would be
x=
2a
−b±
b
2
−4ac

4 0

3 years ago

Estimate the square root of 150 to the nearest tenth.

muminat

the answer is 12.2 for 150 rounded to nearest tenth

5 0

2 years ago

Read 2 more answers

What are the missing angles? What is the relationship between the measures of supplementary angles?

goldenfox [79]

Answer:

6=100°

8=80°

7=100°

9=80°

Step-by-step explanation:

If 6 is 100°

in a straight line theres 180 degrees

180-100=80°

8 is 80°

opposite 6 to 7 there are parallel corresponding angles meaning the angle opposite it will be the same. 8 with 9.

same with

5 0

2 years ago

Help please..................

Svetradugi [14.3K]

Substitute p and q with the given numbers (6 and 5) then use pemdas
18+42/6-5= 20

4 0

2 years ago

Read 2 more answers

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Step2247 [10]

Answer:

$A = 297\pi$

Step-by-step explanation:

To solve this problem we need to be familiar with the formula for the surface area of a cone:

$A = \pi r(r + \sqrt{h^2+r^2})$

We are given the length of a side and the diameter, to calculate the radius divide the diameter in half:

$r = \frac{d}{2}\\r = \frac{18}{2}\\r = 9 cm$

To calculate the height of the cone, we must use the Pythagorean Theorem:

$C^2 = A^2 + B^2$

We can treat the side length as the hypotenuse $C$ , the radius as the base $A$ , and solve for height $B$ . Set the expression up like this:

$C^2 = A^2 + B^2\\24^2 = 9^2 + B^2\\B^2 = 24^2 - 9^2\\B = \sqrt{24^2 - 9^2}\\B = \sqrt{576 - 81}\\B = \sqrt{495}\\B \approx 22.25$

Now we can plug into our original formula:

$A = \pi r(r + \sqrt{h^2+r^2})\\A = \pi 9(9+\sqrt{\sqrt{495}^2+9^2}\\A = \pi 9(9+\sqrt{495 + 81}\\A = \pi 9(9+\sqrt{576})\\A = \pi 9(9 + 24)\\A = \pi 9(33)\\A = 297\pi$

5 0

1 year ago