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Fofino [41]
3 years ago
9

on a scale drawing, a tree is 6 3/4 inches tall. the scale factor is 1/20. find the height of the actual tree.

Mathematics
2 answers:
Hoochie [10]3 years ago
8 0
I think the answer is 15
 
Verdich [7]3 years ago
4 0
To solve this problem you could set up a proportion 1/20=6.75/x. Next you would use property of cross products to get 20*6.75=x. Just mulitply to solve you should get 135 inches. To find the answer in ft just divide by 12
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Pls help i dont get how to do this
Lorico [155]

Step-by-step explanation:

What this is saying is...20 is a whole number; but 3/4 is not. What they are saying is, if you have to add a mixed number with a whole number, you can add both of the whole numbers together. Then, you add the 3/4 at the end...because it is not a whole number. You can break apart a mixed number by separating the whole number and the fraction.

Hope this helps :)

3 0
3 years ago
What is tan 45°? √2 1 45° 90° A. √2 ​
yarga [219]

Answer:

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6 0
2 years ago
Y=-2x-21 determine the intercepts of the line (,) (,) ASAPPPP
Nesterboy [21]

Answer:

x intercept (10.5,0)

y intercept (0, -21)

Step-by-step explanation:

y=-2x-21

there are two intercept for a line

x intercept, the point of given equation of  line which lies on x axis.

For x intercept corodinate of y is o

Thus, value x intercept is form (x,0)

putting these value in y=-2x-21, we find x intercept

0=-2x-21

2x = 21

x = 21/2 = 10.5

Thus, x intercept (10.5,0)

Y intercept, the point of given equation of  line which lies on y axis.

For Y intercept coordinate of x is o

Thus, value y intercept is form (0,y)

putting these value in y=-2x-21, we find y intercept

y = -2*0 -21

y = -21

Thus, y intercept (0, -21)

5 0
3 years ago
Due to gravity, objects weigh three times as much on Earth as they do on Mercury.
SpyIntel [72]

Answer:

If an object on Mercury weighed 25lb, it would weigh 75lb on Earth

(25 * 3 = 75)

The answer is b  

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6 0
3 years ago
Please help. solve for x
malfutka [58]

Step-by-step explanation:

Given,

Base of the triangle

2 \sqrt{6}

Hypotenuse of the triangle = 5

Height of the triangle = x

Therefore, According to Pythagoras Theorem,

{base}^{2}  +  {height}^{2}  =  {hypotenuse}^{2}

=  >  {(2 \sqrt{6)} }^{2}  +  {x}^{2}  =  {5}^{2}

=  > 24 +  {x}^{2}  = 25

=  >  {x}^{2}  = 25 - 24

=  >  {x}^{2}  = 1

=  > x =  \sqrt{1}

=  > x = 1

Hence, the required value of <u>x is 1.</u>

7 0
2 years ago
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