Draw the lewis structure of the hypochlorite ion, . include lone pairs.
2 answers:
Answer :
Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The electrons are represented by dot.
The given molecule is, hypochlorite ion.
Chlorine has '7' valence electrons and oxygen has '6' valence electron.
Therefore, the total number of valence electrons in hypochlorite ion, = 7 + 6 + 1 = 14
According to electron-dot structure, there are 2 number of bonding electrons and 12 number of non-bonding electrons.
The Lewis-dot structure of hypochlorite ion is shown below.
Lewis structures are also known as Lewis dot diagrams or Lewis dot formulas. This <span>diagrams depict the </span>bonding<span> between </span>atoms<span> of a </span>molecule<span> and the </span>lone pairs<span> of </span>electrons<span> that may exist in the molecule. </span><span>A Lewis structure can be drawn for both </span>covalently <span>bonded molecule and </span><span>coordination compounds.
The l</span>ewis structure of the hypochlorite ion is attached below. From the lewis structure, it can be seen that, in hypochlorite ion Cl and O shares one pair of electrons. Hence, bond order of<span> hypochlorite ion is one. </span>
The l</span>ewis structure of the hypochlorite ion is attached below. From the lewis structure, it can be seen that, in hypochlorite ion Cl and O shares one pair of electrons. Hence, bond order of<span> hypochlorite ion is one. </span>
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Answer: 51.45 grams of excess reagent is left after the completion of reaction.
Explanation: For the calculation of moles, we use the formula:
....(1)
- For Si
Given mass = 92 grams
Molar mass = 28g/mol
Putting values in equation 1, we get:
- For
Given mass = 112 grams
Molar mass = 116g/mol
Putting values in equation 1, we get:
The reaction follows:
By Stoichiometry,
2 moles of reacts with 3 moles of silicon
So, 0.965 moles of reacts with =
= 1.4475 moles of Silicon.
As, the moles of silicon is more than the required amount and is present in excess.
So, the excess reagent for the reaction is Silicon.
Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles
To calculate the amount of Silicon left in excess is calculated by using equation 1:
Amount of Silicon in excess will be 51.45 grams.