Answer:
N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)
Explanation:
The half reaction for the reaction for the reduction of gaseous nitrogen to aqueous hydrazine is;
N₂(g) → N₂H₄(aq)
The balancing the atoms in the half reaction. Hydrogen atom is balanced by adding hydrogen ions (H⁺)
We have;
N₂(g) + 4H⁺(aq) → N₂H₄(aq)
Then we balance the charge on both sides by adding electrons where the positive charge is greater;
we have;
N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)
Answer: 51.45 grams of excess reagent is left after the completion of reaction.
Explanation: For the calculation of moles, we use the formula:
....(1)
Given mass = 92 grams
Molar mass = 28g/mol
Putting values in equation 1, we get:

- For

Given mass = 112 grams
Molar mass = 116g/mol
Putting values in equation 1, we get:

The reaction follows:

By Stoichiometry,
2 moles of
reacts with 3 moles of silicon
So, 0.965 moles of
reacts with =
= 1.4475 moles of Silicon.
As, the moles of silicon is more than the required amount and is present in excess.
So, the excess reagent for the reaction is Silicon.
Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles
To calculate the amount of Silicon left in excess is calculated by using equation 1:

Amount of Silicon in excess will be 51.45 grams.