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3 years ago

Write a balanced half-reaction for the reduction of gaseous nitrogen (N2) to aqueous hydrazine (N2H4) in basic aqueous solution.

Chemistry

1 answer:

weqwewe [10]3 years ago

5 0

Answer:

N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)

Explanation:

The half reaction for the reaction for the reduction of gaseous nitrogen to aqueous hydrazine is;

N₂(g) → N₂H₄(aq)

The balancing the atoms in the half reaction. Hydrogen atom is balanced by adding hydrogen ions (H⁺)

We have;

N₂(g) + 4H⁺(aq) → N₂H₄(aq)

Then we balance the charge on both sides by adding electrons where the positive charge is greater;

we have;

N₂(g) + 4H⁺(aq) + 4e⁻ → N₂H₄(aq)

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Answer:

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Explanation:

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Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = $\frac{0.1028 mol}{0.1 L}=1.028 mol/L$

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Molarity of the solution before dilution = $M_1=1.208 mol$

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$M_1V_1=M_2V_2$

$M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}$

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Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

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Moles of glucose = $0.07248 mol/L\times 0.1 L=0.007248 mol$

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Explanation:

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