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max2010maxim [7]
3 years ago
13

Tony's hourly wage is $20 and his net pay is 75% of his earnings. Tony spends about $1,900 on his monthly expenses. If Tony work

s 40 hours per week and has no other sources of income, what is his net monthly cash flow?
Mathematics
1 answer:
Westkost [7]3 years ago
8 0

Answer:

The net monthly cash flow is $500

Step-by-step explanation:

The computation of the net monthly cash flow is shown below:

= Earnings - expense

where,

Earnings is

= Hourly wage rate × number of hours worked per week × given percentage × number of weeks in a month

= $20 × 40 hours × 75% × 4

= $2,400

And, the monthly expense is $1,900

So, the net monthly cash flow is

= $2,400 - $1,900

= $500

hence, the net monthly cash flow is $500

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Answer:

The value to the given expression is 8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Step-by-step explanation:

Given expression is (StartFraction (10 Superscript 4 Baseline) (5 squared) Over (10 cubed) (5 cubed)) cubed

Given expression can be written as below

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3

To find the value of the given expression:

\left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=\frac{((10^4)(5^2))^3}{((10^3)(5^3))^3}

( By using the property ((\frac{a}{b})^m=\frac{a^m}{b^m} )

=\frac{(10^4)^3(5^2)^3}{(10^3)^3(5^3)^3}

( By using the property (ab)^m=a^mb^m )

=\frac{(10^{12})(5^6)}{(10^9)(5^9)}

( By using the property (a^m)^n=a^{mn} )

=(10^{12})(5^6)(10^{-9})(5^{-9})

( By using the property \frac{1}{a^m}=a^{-m} )

=(10^{12-9})(5^{6-9}) (By using the property a^m.b^n=a^{m+n} )

=(10^3)(5^{-3})

=\frac{10^3}{5^3} ( By using the property a^{-m}=\frac{1}{a^m} )

=\frac{1000}{125}

=8

Therefore \left[\frac{(10^4)(5^2)}{(10^3)(5^3)}\right]^3=8

Therefore the value to the given expression is 8

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