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Radda [10]
3 years ago
10

The image of trapezoid PQRS after a reflection across Line W Y is trapezoid P'Q'R'S'. 2 trapezoids are shown. Line W Y is the li

ne of reflection. Line segment R R prime has a midpoint at point Z. Line segment S S prime has a midpoint at point X. What is m? 45º 90º 180º 270º
Mathematics
2 answers:
RoseWind [281]3 years ago
3 0

Answer:

90

Step-by-step explanation:

harina [27]3 years ago
3 0

Answer:

90

Step-by-step explanation:

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Can someone help me graph this and solve the problem thank you
Marizza181 [45]
Y - 3 = -1/4(x - 4)
y - 3 = -1/4x + 1
y = -1/4x + 1 + 3
y = -1/4x + 4

ok....the y int is (0,4)....the slope is -1/4...
       x int can be found by subbing in 0 for y and solving for x
       y = -1/4x + 4
       0 = -1/4x + 4
       1/4x = 4
       x = 4 * 4
       x = 16....so ur x int is (16,0)

so first plot ur points (0,4)....and since ur slope is -1/4, go down 1 space and to the right 4 spaces, then down 1, and to the right 4....keep doing this and u will cross the x axis at (16,0)
6 0
4 years ago
Does someone know this?
sergejj [24]

Answer:

l=12in×4=48in

w=8in×4=32in

A1=32in×48in=1536in²

5 0
2 years ago
A store pays $427 for a gymnastics mat.The store marks up the price by 38%.What is the amount of the mark-up? giving crown
kati45 [8]

Answer:

589.26

Step-by-step explanation:

427*.38=162.26

162.26+427=589.26

3 0
3 years ago
Benjamin is trying to find the height of a radio antenna on the roof of a local building.
xz_007 [3.2K]

The height of the antenna on the roof of the local building is approximately 8 meters.

The situation forms a right angle triangle.

<h3>Properties of a right angle triangle:</h3>
  • One of its angles is equals to 90 degrees
  • The sides of the triangles can be calculated using Pythagoras theorem.

Therefore, let's find the height of the building and the radio antenna from the eye point.

Using trigonometric ratios,

tan 40° = opposite / adjacent

tan 40° = x / 25

where

x = the height of the building and the radio antenna from the eye point.

x = 25 tan 40

x = 25 × 0.83909963117

x = 20.9774907794 meters

Let's find the height of the building from his eye point.

tan 28° = y / 25

where

y = height of the building from his eye point

y = 25 × tan 28°

y = 25 × 0.53170943166

y = 13.2927357915 meters

Height of the antenna = 20.9774907794 - 13.2927357915 = 7.68475498786

Height of the antenna ≈ 8 meters

learn more on elevation here: brainly.com/question/17582385?referrer=searchResults

8 0
3 years ago
If the perimeter of a rectangular picture frame must be less than 180 in, and the width is 26 in, what must the height h of the
valentinak56 [21]
You would form this inequality:

52 + 2x < (or equal to) 180

Then, solve as you would in an ordinary equation.

Subtract 52 from both sides of the sign. 180 - 52 = 128.

So, 2x is less than or equal to 128.
Divide 128 into two to get 64.

The height of the frame must be 64 inches.
4 0
4 years ago
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