Answer:
We can graph y = 2x/3 - 2 to find the line.
We know one point, which is the y-intercept. The y-intercept is (0,-2) so that is our first point. Plot that point on the chart. Now to find another point, we can just insert a number for x and solve for y. I am going to use the number 3.
y = 2x/3 - 2
y = 2(3)/3 - 2
y = 6/3 - 2
y = 2 - 2
y = 0
So when x = 3 y = 0. We have another point,which is (3,0) Plot the points (0, -2) (3, 0) and draw a line between the points and that is your graph.
there ya go
i dont quite get the question but...
i guess this is how it is.
Take the mirror image of∆ABC Through the a line through the point y=3.
The new ∆ABC would have point C=(4,2)
B=(3,-6) A=(1,-3)
Now shifting the ∆ABC one unit (<em>i.e. 2 acc. to the graph as scale is 1 unit =2</em>) towards right ( or <em>adding 2 to the x coordinates of ∆ABC)</em>
We get the Coordinates of triangle ABC as A=(3,-3) B=(5,-6) C=(6,2).
This coordinate is the same coordinates of ∆A"B"C".
Hope it helps...
Regards;
Leukonov/Olegion.
0.18 because the third decimal place is less than 5
To find the expected value of your gain in each prize, subtract the price of the ticket from the prize:
If the prize is $500: $500 - $2 = $498
If the prize is $250: $250 - $2 = 248
If the prize is $160: $160 - $2 = $73
But if you did not win any cash prize, you do not have any gain because
0 cash prize - $2 ticket = -$2 which is a loss
