Turn F(x) into vertex form:
y=x^2+8x+6
y-6=x^2+8x
y-6+16=x^2+8x+16
y+10=(x+4)^2
Thus the vertex is (-4,-10)
This is a minimum because the parabola is up up, or is positive
Answer:
No solution
Step-by-step explanation:
see the steps below:)
Answer: 
Step-by-step explanation:
Given
Here the given figure can be divided into two shapes i.e. rectangle and a trapezium
For rectangle ABCD Area = 
Area of trapezium CEFD Area is ![\frac{1}{2}[\text{sum of non-parallel sides}]\times[\text{distance between them}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%5Ctext%7Bsum%20of%20non-parallel%20sides%7D%5D%5Ctimes%5B%5Ctext%7Bdistance%20between%20them%7D%5D)
Total shaded area 
Answer:
I believe the reflection line will be on x=1
Step-by-step explanation:
I tend to eyeball the reflection line to make it symmetrical, if I'm not much of a help I apologize
Answer:
10x² - 8x - 24
Step-by-step explanation:
Given
(2x - 4)(6 + 5x)
Each term in the second factor is multiplied by each term in the first factor, that is
2x(6 + 5x) - 4(6 + 5x) ← distribute both parenthesis
= 12x + 10x² - 24 - 20x ← collect like terms
= 10x² - 8x - 24