From 8:25 to 30 seconds past 8:29 is 4.5 minutes.
This means she rode her bike 3/4 mile in 4.5 minutes.
Calculate her speed per mile:
1 mile / 0.75 = 1.333
4.5 minutes * 1.333 = 6 minutes per mile.
She needs to ride 3.42 miles, so multiply distance by speed:
3.42 miles x 6 minutes per mile = 20.52 minutes.
0.52 * 60 = 31.2 seconds.
This means it will take a total of 20 minutes and 31 seconds to get from her house to school.
She left at 8:25, add her travel time:
8:25 + 20 minutes and 31 seconds = 8:45 and 31 seconds.
This is sooner than the time school starts so she makes it on time.
Answer:
An example is x^2 + x - 2 = 0.
Step-by-step explanation:
An equation of degree 2 is one where there the highest degree is 2 like the x^2 in the answer.
Answer:
<em>D:5(x2 + 6x ___) + 15 ___ = 0</em>
Step-by-step explanation:
<u>Parabola in Vertex Form</u>
To express the equation of a parabola in vertex form we must complete squares. The equation is given as
![5x^2 + 30x + 15 = 0](https://tex.z-dn.net/?f=5x%5E2%20%2B%2030x%20%2B%2015%20%3D%200)
The first step is to factor 5 and leave space to complete the third term in the parentheses, along with a space outside it to compensate. This should look like
![5(x^2 + 6x\text{........)} + 15....... = 0](https://tex.z-dn.net/?f=5%28x%5E2%20%2B%206x%5Ctext%7B........%29%7D%20%2B%2015.......%20%3D%200)
Those spaces need to be filled out like shown in the step 2. Thus the correct option is D
Answer:
![\Huge \boxed{x=-1}](https://tex.z-dn.net/?f=%5CHuge%20%5Cboxed%7Bx%3D-1%7D)
Step-by-step explanation:
![x^2+2x=-1](https://tex.z-dn.net/?f=x%5E2%2B2x%3D-1)
Adding 1 to both sides of the equation.
![x^2+2x+1=-1+1](https://tex.z-dn.net/?f=x%5E2%2B2x%2B1%3D-1%2B1)
![x^2 +2x+1=0](https://tex.z-dn.net/?f=x%5E2%20%2B2x%2B1%3D0)
Factoring the left side of the equation.
![x^2 +1x+1x+1=0](https://tex.z-dn.net/?f=x%5E2%20%2B1x%2B1x%2B1%3D0)
![x(x+1)+1(x+1)=0](https://tex.z-dn.net/?f=x%28x%2B1%29%2B1%28x%2B1%29%3D0)
![(x+1)(x+1) = 0](https://tex.z-dn.net/?f=%28x%2B1%29%28x%2B1%29%20%3D%200)
![(x+1)^2 =0](https://tex.z-dn.net/?f=%28x%2B1%29%5E2%20%3D0)
Taking the square root of both sides of the equation.
![\sqrt{(x+1)^2} =\sqrt{0}](https://tex.z-dn.net/?f=%5Csqrt%7B%28x%2B1%29%5E2%7D%20%3D%5Csqrt%7B0%7D)
![x+1=0](https://tex.z-dn.net/?f=x%2B1%3D0)
Subtracting 1 from both sides of the equation.
![x+1-1=0-1](https://tex.z-dn.net/?f=x%2B1-1%3D0-1)
![x=-1](https://tex.z-dn.net/?f=x%3D-1)
Try this website! http://www.themathpage.com/aprecalc/rational-functions.htm