Simplify (6b^2)^2 Please hurry !!
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Answer: See figure 2 in the diagram below for the table.
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Explanation:
The steps are fairly lengthy to explain in words, but the process is fairly straightforward. Start with figure 1 in the diagram below. The letters A through O represent the steps you'll take to replace them. For instance, you'll replace A with 219 since that's the grand total. Then B is replaced with 137 since we're told that 137 girls were surveyed. Then C gets replaced with 219-137 = 82, and so on. Use arithmetic (adding and subtracting) to gradually replace each letter with the proper number as figure 2 shows. The alphabetical order directly corresponds to the order in which the values are given by your teacher (eg: 219 is first, then 137 next, and so on).
Let me know if you get stuck on any one step, or need me to go into more detail.
The smallest such number is 1055.
We want to find such that
The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.
Taking everything together, we end up with the system
Now the moduli are coprime and we can apply the CRT.
We start with
Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.
Taken modulo 2, we end up with
which means the first term is fine and doesn't require adjustment.
Taken modulo 3, we have
We want a remainder of 2, so we just need to multiply the second term by 2.
Taken modulo 5, we have
We want a remainder of 0, so we can just multiply this term by 0.
Taken modulo 7, we have
We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since , the inverse of 2 is 4.
So, we have to adjust to
and from the CRT we find
so that the general solution for all integers
.
We want a 4 digit solution, so we want
which gives .