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Darya [45]
3 years ago
9

Mark tossed six balls while playing number game. Three balls landed in one section and three balls landed in another section, hi

s score is greater than one hundred thousand. What could be his score? How can you use what you know about place value to find what Mark's score could be?
Mathematics
1 answer:
Vlad1618 [11]3 years ago
7 0
The answer is 3 for sure 100%sure
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Find the equation of a line that is perpendicular to 4y-3x=1 and passes through point (-7,0).
Mnenie [13.5K]

Answer:

-4/3x + -28/3

Step-by-step explanation:

First you rearrange 4y-3x=1

y= 3/4x +1/4

then you reciprocate and change the sign the slope since you are trying to find a line perpendicular to it.

Slope(m) =-4/3

then you use the formula <em>y-y1= m(x-x1)</em>

y-0= -4/3 (x--7)

y= -4/3 +-28/3

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What is answer if 2xyx5​
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Answer:

Answer is 3bu2(DeEZ)=1

Step-by-step explanation:

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In the accompanying diagram PA is tangent to circle 0 at A if CN=12 and PB=4 what is the length of PA?
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Please help ‼️ <br><br> Today's date is 28. What is half the date?
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8 0
2 years ago
Consider the population of all 1-gallon cans of dusty rose paint manufactured by a particular paint company. Suppose that a norm
Artemon [7]

Answer:

a) 0.5.

b) 0.8413

c) 0.8413

d) 0.6826

e) 0.9332

f) 1

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 6, \sigma = 0.2

(a) P(x > 6) =

This is 1 subtracted by the pvalue of Z when X = 6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6-6}{0.2}

Z = 0

Z = 0 has a pvalue of 0.5.

1 - 0.5 = 0.5.

(b) P(x < 6.2)=

This is the pvalue of Z when X = 6.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

(c) P(x ≤ 6.2) =

In the normal distribution, the probability of an exact value, for example, P(X = 6.2), is always zero, which means that P(x ≤ 6.2) = P(x < 6.2) = 0.8413.

(d) P(5.8 < x < 6.2) =

This is the pvalue of Z when X = 6.2 subtracted by the pvalue of Z when X  5.8.

X = 6.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.2-6}{0.2}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 5.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

(e) P(x > 5.7) =

This is 1 subtracted by the pvalue of Z when X = 5.7.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5.8-6}{0.2}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

1 - 0.0668 = 0.9332

(f) P(x > 5) =

This is 1 subtracted by the pvalue of Z when X = 5.

Z = \frac{X - \mu}{\sigma}

Z = \frac{5-6}{0.2}

Z = -5

Z = -5 has a pvalue of 0.

1 - 0 = 1

5 0
3 years ago
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