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timofeeve [1]
2 years ago
8

Write the value on the number line next to letter

Mathematics
2 answers:
tatyana61 [14]2 years ago
8 0

Answer:

where is the letter???

Zolol [24]2 years ago
7 0
I dont see it though
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A TV that usually sells for $192.15 is on sale for 20% off. If sales tax on the TV is 6%, what is the price of the TV, including
faust18 [17]

Answer:

$162.94

Step-by-step explanation:

Because 20% off of 192.15 = $162.94 and

$153.72  + (6.0%) $9.22  = $162.94

8 0
2 years ago
walnut grower estimates from past records that if 20 trees are planted per acre, then each tree will average 60 pounds of nuts p
laila [671]

Answer:

5 trees should be planted to maximize the yield per acre,

The maximum yield would be 1250

Step-by-step explanation:

Given,

The original number of trees per acre = 20,

Average pounds of nuts by a tree = 60,

Let x be the times of increment in number of trees,

So, the new number of trees planted per acre = 20 + x

∵ for each additional tree planted per acre, the average yield per tree drops 2 pounds,

So, the new number of pounds of nut = (60 - 2x)

Thus, the total yield per acre,

Y(x) = (20+x)(60-2x)

Differentiating with respect to t ( time ),

Y'(x) = (20+x)(-2) + 60 - 2x = -40 - 2x + 60 - 2x = 20 - 4x

Again differentiating with respect to t,

Y''(x) = -4

For maxima or minima,

Y'(x) = 0

⇒ 20 - 4x = 0

⇒ 20 = 4x

⇒ x = 5,

For x = 5, Y''(x) = negative,

Hence, Y(x) is maximum for x = 5,

And, maximum value of Y(x) = (20+5)(60 - 10) = 25(50) = 1250,

i.e. 5 trees should be planted to maximize the yield per acre,

and the maximum yield would be 1250 pounds

4 0
2 years ago
6÷2(1+2)=?
mina [271]
I don't have the answer for the second one, but the answer to number 1 is 9.

6÷2(1 + 2) =

6÷2(3) =

3(3) =

9
5 0
3 years ago
5.012121212<br> rational or irrational?
Inga [223]

Answer:

rational

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
3 0
2 years ago
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