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Given that the ball has a thickness of 1 cm and the radius at the outside is 5 cm, thus the radius from inside is 5 - 1 = 4cm.
The <span>approximate volume of rubber used to make the ball is given by the volume of the ball at the outside surface minus the volume of the ball at the inside surface.
i.e.
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<span>
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The <span>approximate volume of rubber used to make the ball is given by the volume of the ball at the outside surface minus the volume of the ball at the inside surface.
i.e.
</span>
<span>
Now, the cosecant of θ is -6, or namely -6/1.
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,
however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.
we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now
recall that
therefore, let's just plug that on the remaining ones,
now, let's rationalize the denominator on tangent and secant,