I think it’s Cytokinesis.
The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
Answer:
here is the order
Genetics
Allele
Hybrid then law of independent assortment
Law of segregation
mRNA will serve as reference book that contains information as the DNA and its sequence is complementary to the DNA template.
The transfer of information in a DNA strand to a new molecule
of messenger RNA is known as transcription. Thus, the process of transcription
is carried out by an enzyme called RNA polymerase and a number of accessory
proteins called transcription factors. However, DNA is copied into mRNA because mRNA will serve as
reference book that contains information as the DNA and its sequence is
complementary to the DNA template.
