Sorry, it's late, and I'm a bad explainer.
The error is adding (2x-12) with x and 30. This is wrong because you are adding the angles inside the triangle and you are assuming that (2x - 12) is the unlabeled angle INSIDE the triangle, when it is the exterior angle/outside of the triangle.
A straight line is also 180°.
(2x - 12) + ? = 180
30 + x + ? = 180
If you look at the equations, and put parentheses around 30 + x, (30 + x) and (2x - 12) should be the SAME NUMBER. So you could set them equal to each other to find x. (or you could also look at the picture and see that they both need/are missing the same angle)
2x - 12 = 30 + x
x = 42
Now you plug 42 into the exterior angle equation
2(42) - 12 = 84 - 12 = 72°
Answer:
Step-by-step explanation:
The equation of a circle with center (a,b) and radius r, is
From the question, the center of the circle is located at (-6,2) and the radius is
We substitute the center and radius to get:
Simplify to obtain:
Im not too sure but i would say 27
Answer:
(x + 2)² + (y + 9)² = 49
Step-by-step explanation:
Equation:
(x - h)² + (y - k)² = r²
(x - -2)² + (y - -9)² = 7²
(x + 2)² + (y + 9)² = 49
