Here,
let width(b)be x then,
length (l)=9cm+x
area =112 sq cm
now,
area of rectangle=l*b
or, 112=(9+x)x
or, 112=9x+x^2
or, 0=x^2+9x-112
or, 0=x^2+(16-7)x-112
or, 0=x^2+16x-7x-112
or, 0=x(x+16)-7(x+16)
or, 0=(x-7)(x+16)
either,
0=x-7
or,7=x
x=7cm
Or,
0=x+16
or, -16=x
x= -16[impossible,as distance is never negative] so,
x=7cm
therefore,length = 7cm + 9 cm = 16cm and width = 7cm.
;)
The answer is (5,3). You need to equal both sides out. So 5x-22=4x-17. That will give you x=5. After that you substitute 5 for x in one or both of the equations and get that y=3. Hope this helps!
F(x)=|x-5|+2
plug it in
so f(3)
f3)=|3-5|+2
solve whats inside first
|-2|+2
since its absolute value its actually positive
2+2
4
Your answer is C.) 4
Answer:
a=4
Step-by-step explanation:
you subtract the 5 from both sides and then you divide the 3 into the three and then you have 4
All number dived in it same vale are =1
