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2 years ago

11

Need help with this please dont cheat and put just b#l1$H!t

1 answer:

DIA [1.3K]2 years ago

4 0

Answer:

B (ignore this its for 20 characters

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Arrange the summation expressions in increasing order of their values.

dolphi86 [110]

∑ 4 * 5^(i-1) = 4 + 20 + 100 + 500 = 624
∑ 3 * 4^(i-1) = 3 + 12 + 48 + 192 + 768 = 1,023
∑ 5* 6^(i-1) = 5 + 30 = 35
∑ 5^(i-1) = 1 + 5 + 25 + 125 = 156
Answer:
∑ (i=1, 2) 5 * 6^(i-1) < ∑ (i=1, 4) 5^(i-1) < ∑ (i=1, 4) 4 * 5^(i-1) <
< ∑ (i=1, 5) 3 * 4^(i-1)

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3 years ago

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Divide 72 in the ratio 7:2.<br> show your work.

AVprozaik [17]

I think the answer is 3.5 cause when you divide it 7 go inside and 7 there's nothing you can multiply to get 7

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3 years ago

A group of students are planning a mural at a wall the rectangular wall has dimensions of (6x+7) by (8x+5) and they are planning

zvonat [6]

Answer: $46x^2+73x+15$

Step-by-step explanation:

The area of a rectangle can be calculated with the formula:

$A=lw$

l: the length of the rectangle.

w: the width of the rectangle.

The area of the remaning wall after the mural has been painted, will be the difference of the area of the wall and the area of the mural.

Knowing that the dimensions of the wall are $(6x+7)$ by $(8x+5)$ , its area is:

$A_w=(6x+7)(8x+5)\\\\A_w=48x^2+30x+56x+35\\\\A_w=48x^2+86x+35$

As they are planning that the dimensions of the mural be $(x+4)$ by $(2x+5)$ , its area is:

$A_m=(x+4)(2x+5)\\\\A_m=2x^2+5x+8x+20\\\\A_m=2x^2+13x+20$

Then the area of the remaining wall after the mural has been painted is:

$A_{(remaining)}=A_w-A_m\\\\A_{(remaining)}=48x^2+86x+35-(2x^2+13x+20)\\\\A_{(remaining)}=48x^2+86x+35-2x^2-13x-20\\\\A_{(remaining)}=46x^2+73x+15$

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3 years ago

Use PEMDAS to evaluate the expression 8 x 4 − 21 ÷ 3 + 5.<br><br> 30<br> 32<br> 34<br> 36

VikaD [51]

the answer should be 30

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2 years ago

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A watering can dispenses water at a rate of 0.40 gallon per minute. The original volume of water in the can was 10 gallons. Whic

andreev551 [17]

The correct answer is B.

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3 years ago

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