(1.) 35-3m
m= 4
35-3m
= 35-3(4)
= 35-12 (do the multiple/division first before doing the addition/subtraction)
= 23
C. 23
(2.) 1 + x ÷ 5
x = 80
1 + x ÷ 5
= 1+80÷5
= 1+16
= 17
(3.) mx-y
m=5, x=3, and y=8
mx-y
= 5(3)-8
= 15-8
= 7
(4.) 3a+15+bc−6
a=7, b=3, and c=15
3a+15+bc-6
= 3(7)+15+3(15)-6
= 21+15+45-6
= 75
Answer:
15x-8
Step-by-step explanation:
9x-12+4x+4+10x
9x+4x+10x -12+4
15x-8
Answer:
option D
Step-by-step explanation:
for x intercept
the curve crosses the x asis at 1
then for y intercept it crosses the y axis at-2
that's all...have fun
Check the picture below.
is not very specific above, but sounds like it's asking for an equation for the trapezoid only, mind you, there are square tiles too.
but let's do the trapezoid area then,
![\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad \sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\ -------------------------------\\\\](https://tex.z-dn.net/?f=%5Cbf%20a%5E%7B%5Cfrac%7B%7B%20n%7D%7D%7B%7B%20m%7D%7D%7D%20%5Cimplies%20%20%5Csqrt%5B%7B%20m%7D%5D%7Ba%5E%7B%20n%7D%7D%20%5Cqquad%20%5Cqquad%0A%5Csqrt%5B%7B%20m%7D%5D%7Ba%5E%7B%20n%7D%7D%5Cimplies%20a%5E%7B%5Cfrac%7B%7B%20n%7D%7D%7B%7B%20m%7D%7D%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C)
Answer:
may have different df values but they all have the same denominator
Step-by-step explanation:
In a two-factor analysis of variance, the F-ratios for factor A, factor B, and the AxB interaction _____. may have different df values but they all have the same denominator
In two--factor analysis of variance, the estimates of the variance can be obtained by partitioning the total sum of squares into three components corresponding to the three possible sources of variation , viz; Between Rows, Between Columns, and Within Samples or error.
As the number of rows and columns may differ the degrees of freedom differ with them.
In other words
Total df= Rows df + Columns df + Error df
Since the variance is identically the same for each row of the c values and variance is the same for each observation in the jth column of r values the sum of squares becomes an identity.
Therefore it may have different df values but they all have the same denominator.
